Question

plz help

Answer 1

\[\tan \theta=\frac{ -5 }{ 5 }=-1=-\tan 45=\tan (360-45)=\tan 315\]
\[\theta=315\]
\[\sin 315=\sin (360-45)=-\sin 45=-\frac{ 1 }{ \sqrt{2} }=\frac{ 5 }{ -5\sqrt{2} }\]

Answer 2

or
length of terminal point to origin
\[=\sqrt{5^2+(-5)^2}=\sqrt{25+25}=\sqrt{50}=5\sqrt{2}\]
\[\sin \theta=\frac{ ordinate }{ radius ~vector }=\frac{ -5 }{ 5\sqrt{2}}=\frac{ 5 }{ -5\sqrt{2} }\]