A charge of 5 x10-9 C is attracted by a charge of –3x10-7 C with a force of 0.135 N. How far apart are they? (Hint: manipulate the equation to get an expression for d)

Question

A charge of 5 x10-9 C is attracted by a charge of –3x10-7 C with a force of 0.135 N. How far apart are they? (Hint: manipulate the equation to get an  expression for d)

Tranquility · Answer

You have to use Coulomb's law

Tranquility · Answer

$\Large F = k\dfrac{Q_1 Q_2}{d^2}$

F = Force = 0.135 N
charge 1 = Q1 = 5 * 10^-9 C
charge 2 = Q2 = -3 * 10^-7 C
k = Coulomb's constant = 8.9875 * 10^9 N*m^2/C^2
distance = d = ??

Solve for d which is the distance between those two charges

1 attachment