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In a molecule of calcium sulfide, calcium has two valence electron bonds, and a sulfur atom has six valence electrons. How many lone pairs of electrons are present in the Lewis structure of calcium sulfide? A. one B. two C. three D. four E. none
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It should be two lone pairs. The sulfur takes two electrons from the calcium and pairs them with 2 of its own, I believe. So sulfur has 4 other electrons, or 2 lone pairs.
The answer is D which is four Ca has given up 2 electrons to sulfur with six which makes 8 e-, or 4 pairs
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