How many grams of carbon dioxide (CO2) are produced when 124 grams of sugar are used in a recipe? 60.6 g CO2 30.3 g CO2 121.2 g CO2
They gave me this C6H12O6
>2C2H6OH + 2CO2
C6 H12 O6
> 2C2 H6 OH + 2CO2
Ight thanks
@kekeman is this a test question?
Nope this is for my study guide
These are the options: 60.6 g CO2 30.3 g CO2 121.2 g CO2
And here is the balanced equation: C6 H12 O6|dw:1648485917245:dw| 2C2H5OH + 2CO2
Divide 124g of sugar by the molar mass of sugar (C6H12O6) to get moles sugar. The balanced equation tells you that 1 mol sugar = 2 moles CO2, so multiply moles sugar * 2 to get moles CO2. Finally, multiply by the molar mass of CO2 to get mass of CO2.
So how do you set that up
So 124g divided by 342.3 g/mol
(124g sugar) * (moles sugar)/(molar mass sugar) * (2 moles CO2/ 1 mol sugar) * (g CO2 / moles CO2)
Where do you get 342.3 g/mol? The molar mass of C6H12O6 is 180.16 g/mol
Okay so i got 0.688277087
Ok, that’s your moles sugar, keep going with the rest of the stoichiometry
1.376554174 moles CO2
Good, one last step, multiply by molar mass of CO2
1.376554174 * 44.01 = 60.5821492
Good, that rounds to the answer choice 60.6g
Or 60.6
Thank you i understand now
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