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Chemistry 14 Online
kekeman:

How many grams of carbon dioxide (CO2) are produced when 124 grams of sugar are used in a recipe? 60.6 g CO2 30.3 g CO2 121.2 g CO2

kekeman:

They gave me this C6H12O6


>2C2H6OH + 2CO2

kekeman:

C6 H12 O6


> 2C2 H6 OH + 2CO2

kekeman:

Ight thanks

FantasticlyArtsy:

@kekeman is this a test question?

kekeman:

Nope this is for my study guide

kekeman:

These are the options: 60.6 g CO2 30.3 g CO2 121.2 g CO2

kekeman:

And here is the balanced equation: C6 H12 O6|dw:1648485917245:dw| 2C2H5OH + 2CO2

Vocaloid:

Divide 124g of sugar by the molar mass of sugar (C6H12O6) to get moles sugar. The balanced equation tells you that 1 mol sugar = 2 moles CO2, so multiply moles sugar * 2 to get moles CO2. Finally, multiply by the molar mass of CO2 to get mass of CO2.

kekeman:

So how do you set that up

kekeman:

So 124g divided by 342.3 g/mol

Vocaloid:

(124g sugar) * (moles sugar)/(molar mass sugar) * (2 moles CO2/ 1 mol sugar) * (g CO2 / moles CO2)

Vocaloid:

Where do you get 342.3 g/mol? The molar mass of C6H12O6 is 180.16 g/mol

kekeman:

Okay so i got 0.688277087

Vocaloid:

Ok, that’s your moles sugar, keep going with the rest of the stoichiometry

kekeman:

1.376554174 moles CO2

Vocaloid:

Good, one last step, multiply by molar mass of CO2

kekeman:

1.376554174 * 44.01 = 60.5821492

Vocaloid:

Good, that rounds to the answer choice 60.6g

kekeman:

Or 60.6

kekeman:

Thank you i understand now

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