A triangular prism has a triangular base with dimensions of 3” by 4” by 5” and a volume of 210in^3. What is the surface area of the triangularity prism?
No, your incorrect.
Your finding the surface area. What you said is the volume of the prism.
oh
So, the 3, 4, 5 can be any side. Base side a, base side b, base side c, and height.
i used (Perimeter of the base × Length of the prism) + (2 × Base Area) = (S1 + S2+ S3)L + bh
So two bases are the same length.
Wait, nevermind.
I didn't read the whole question. The whole base is 3,4,5 inches.
We need to find height.
Our values are; Volume - 210^3 Bases - 3,4,5
So, we add the basses, 3,4,5 to get 12.
Then we have to do some calculations with 12 and the volume (210^3).
wait i know how to get it the height is three times the volume, divided by the base's area.
\[h=\frac{ A _{lat} }{ (a+b+c) }\]
The formula for the volume of a pyramid is V = (bh) / 3, where b is the area of the base, and h is the pyramid's height. Re-work the equation to solve for h: h = 3V / b.
No, RP, your actually wrong. With how it has to be done.
I did the calculations that way and it gave me a wrong answer.
oh thats just how i remember it
\[h=\frac{ A _{lat} }{ (3+4+5) }\] \[h=A _{lat}(12)\] \[h=210^3(12)\] \[h=420\div12 = ?\]
So what is 420/12 ?
My bad, 432, not 420.
So 432 divided by 12 is... what, @dominicky
36
yea good job
Correct. So that is your height. I switched things up on accident and did the surface area divided by base and not height times base, my bad. But your final answer for surface area is 432in^2.
@dominicky you should give him best response
I did thank you so much
You're welcome!
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