https://media.edgenuity.com/evresources/656-09-03-00-00_files/i0020000.jpg
In the figure above, according to Kepler’s laws of planetary motion,
a.) A1=A2
b.) Dt1Dt2
c.) if Dt1=Dt2, then the orbit is circular
d.) if Dt1=Dt2, then A1=A2

Question

https://media.edgenuity.com/evresources/656-09-03-00-00_files/i0020000.jpg
In the figure above, according to Kepler’s laws of planetary motion,
a.) A1=A2
b.) Dt1>Dt2
c.) if Dt1=Dt2, then the orbit is circular
d.) if Dt1=Dt2, then A1=A2

BeautyQueen · Answer

The answer is D because  if Δt1 = Δt2, then A1 = A2 pertaining to Kepler's second law that means a planet sweeps out equal areas in equal intervals of time. Which means that if the time intervals (Δt1 and Δt2) are equal then the areas (A1 and A2) must also be equal. Therefore, you can conclude that the A1 = A2 when Δt1 = Δt2 is the true statement and answer.

magicgotthatrizz · Answer

ok