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Chemistry 13 Online
kekeman:

The actual yield of a product in a reaction was measured as 2.80 g. If the theoretical yield of the product for the reaction is 3.12 g, what is the percentage yield of the product? 82.7% 85.2% 87.3% 89.7%

Tranquility:

\(\text{percentage yield} = \dfrac{\text{actual yield}}{\text{theoretical yield}} \times \text{ 100%}\) replace actual yield and theoretical yield with the values that are given in your question and simplify

kekeman:

So 2.80 g/ 3.12 g times 100 is 89.7%

Tranquility:

Good job!

kekeman:

Thx!!!

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