Math

Question

Math>>>

Joe348 · Answer

attachment

jhonyy9 · Answer

how i ve learn in my study log without base mean log base 2

yes ?

Joe348 · Answer

My teacher tells me without base it should be log base 10?

jhonyy9 · Answer

$$\frac{ 1 }{ 3 }\log_{2} 8 = \frac{ 1 }{ 3 }\log_{2} 2^{3} = \frac{ 1 }{ 3 }*3\log_{2} 2 = ?$$

Joe348 · Answer

log 3 ?

jhonyy9 · Answer

really ?

just bc. i ve  learn lg is log base 10

ok let be log base 10

$$\frac{ 1 }{ 3 }\log_{10} 8 = \frac{ 1 }{ 3 }\log_{10}2^{3}= $$

do you can continue it ?

jhonyy9 · Answer

use formula

$$\log_{a} b^{x} = x \log_{a}b$$

Joe348 · Answer

OMG WAIT

Is it just log base 2?

jhonyy9 · Answer

ok in this case use please my first above wrote answer

jhonyy9 · Answer

@jhonyy9 wrote:

$$\frac{ 1 }{ 3 }\log_{2} 8 = \frac{ 1 }{ 3 }\log_{2} 2^{3} = \frac{ 1 }{ 3 }*3\log_{2} 2 = ?$$

continue this

Joe348 · Answer

$$\log base 2 then 2 $$ ?

jhonyy9 · Answer

$$\frac{ 1 }{ 3 }*3 = ?$$

Joe348 · Answer

@jhonyy9 wrote:

$$\frac{ 1 }{ 3 }*3 = ?$$

1

jhonyy9 · Answer

yes

jhonyy9 · Answer

$$\log_{a} a = ?$$

jhonyy9 · Answer

are you here ?

Joe348 · Answer

Yes, sorry I was trying to think

jhonyy9 · Answer

@jhonyy9 wrote:

$$\log_{a} a = ?$$

so = ?

Joe348 · Answer

@jhonyy9 wrote:

$$\log_{a} a = ?$$

so = ?

Is it 1?

jhonyy9 · Answer

exactly

Joe348 · Answer

Thanks dude. It really helped.

jhonyy9 · Answer

@jhonyy9 wrote:

$$\frac{ 1 }{ 3 }\log_{2} 8 = \frac{ 1 }{ 3 }\log_{2} 2^{3} = \frac{ 1 }{ 3 }*3\log_{2} 2 = ?$$

continue this

???

Joe348 · Answer

Wait im confused why are you still quoting that?

jhonyy9 · Answer

@joe348 wrote:

@jhonyy9 wrote:

$$\frac{ 1 }{ 3 }*3 = ?$$

1

jhonyy9 · Answer

@joe348 wrote:

@jhonyy9 wrote:

$$\log_{a} a = ?$$

so = ?

Is it 1?

jhonyy9 · Answer

used these what will get ?

Joe348 · Answer

@jhonyy9 wrote:

used these what will get ?

should be log2 right?

jhonyy9 · Answer

no

$$\frac{ 1 }{ 3 }*3 = 1  $$

the first part of this equation in front of log

$$\log_{a} a = 1 $$

the second part of equation

1*1 = ?

Joe348 · Answer

@jhonyy9 wrote:

no $$\frac{ 1 }{ 3 }*3 = 1 $$ the first part of this equation in front of log $$\log_{a} a = 1 $$ the second part of equation 1*1 = ?

anything times 1 is itself, so 1

jhonyy9 · Answer

yes

jhonyy9 · Answer

@jhonyy9 wrote:

$$\frac{ 1 }{ 3 }\log_{2} 8 = \frac{ 1 }{ 3 }\log_{2} 2^{3} = \frac{ 1 }{ 3 }*3\log_{2} 2 = ?$$

continue this

???

= 1*1 = 1 do you understand it now ?

Joe348 · Answer

@jhonyy9 wrote:

Yes I do, I am just confused on where to put it after log

@jhonyy9 wrote:

$$\frac{ 1 }{ 3 }\log_{2} 8 = \frac{ 1 }{ 3 }\log_{2} 2^{3} = \frac{ 1 }{ 3 }*3\log_{2} 2 = ?$$

continue this

???

= 1*1 = 1 do you understand it now ?

Joe348 · Answer

Btw my response is at the top for some reason

jhonyy9 · Answer

any questions ?

Joe348 · Answer

Just exactly how would i write that ?

Joe348 · Answer

Ah nvm, I got it thanks

jhonyy9 · Answer

anytime np

Joe348 · Answer

Have a good night!

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