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A 4L solution of 1M NaCl is mixed with 3L solution of 1.5M CaCl2 and 3L of 2M solution of AlCl3. What is the final concentration of chloride ions?
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For each component, multiply (concentration)(volune)(# of Cl ions per formula unit) So starting with NaCl, multiply 1M * 4L * 1 Cl per NaCl unit to get 4 moles Cl ions Repeat for all Cl compounds Add the moles of Cl ions Divide by the total volume
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