Question

A goldsmith melts 12.4 grams of gold to make a ring. The temperature of the gold rises from 26°C to 1064°C, and then the gold melts completely. If gold’s specific heat is 0.1291 joules/gram degree Celsius and its heat of fusion is 63.5 joules/gram, how much energy is gained by the gold?

The gold gains a total of _________joules of energy.

Answer 1

Problem One You will use both m * c * deltaT and H = m * heat of fusion. Givens m = 12.4 grams c = 0.1291 t1 = 26oC t2 = 1204 heat of fusion (H_f) = 63.5 J/grams. Equation H = m * c * deltaT + m * H_f Solution H = 12.4 * 0.1291 * (1063 - 26) + 12.4 * 63.5 H = 1660.1 + 787.4 H = 2447.5 or 2447.47 is the exact answer. I have to leave the rounding to you. I have no idea where to round it although I suspect 2450 would be right for 3 sig digs.

Answer 2

Problem Two Formula and Givens t1 = 14.5 t2 = 50.0 E = 5680 c = 4.186 m = ?? E = m c * deltaT Solution 5680 = m * 4.186 * (50 - 14.5) 5680 = m * 4.186 * (35.5) 5680 = m * 148.603 * m m = 5680 / 148.603 m = 38.22 grams That isn't very much. Be very sure you are working in joules. You'd leave that many grams in the kettle after drying it thoroughly. m = 38.2 to 3 sig digs.

Answer 3

Copy and pasted wow

Answer 4

O_O

Answer 5

I have done this question before I use documents

Answer 6

and so yes I copied and pasted my own work now leave me alone

Answer 7

The gold gains a total of _________joules of energy.

Answer 8

Lies
I found your source on brainly

Answer 9

it's 2448 by the way.

Answer 10

brainly?
hell I dont use brainly

Answer 11

moron

Answer 12

o

Answer 13

Problem One

You will use both m * c * deltaT and H = m * heat of fusion.

Givens

m = 12.4 grams

c = 0.1291

t1 = 26oC

t2 = 1204

heat of fusion (H_f) = 63.5 J/grams.

Equation

H = m * c * deltaT + m * H_f

Solution

H = 12.4 * 0.1291 * (1063 - 26) + 12.4 * 63.5

H = 1660.1 + 787.4

H = 2447.5 or 2447.47 is the exact answer. I have to leave the rounding to you. I have no idea where to round it although I suspect 2450 would be right for 3 sig digs.

Problem Two

Formula and Givens

t1 = 14.5

t2 = 50.0

E = 5680

c = 4.186

m = ??

E = m c * deltaT

Solution

5680 = m * 4.186 * (50 - 14.5)

5680 = m * 4.186 * (35.5)

5680 = m * 148.603 * m

m = 5680 / 148.603

m = 38.22 grams That isn't very much. Be very sure you are working in joules. You'd leave that many grams in the kettle after drying it thoroughly.

m = 38.2 to 3 sig digs.

Answer 14

yes I do cause I know that I dont use brainly I use https://answer-ya.com/ as a homework help site as well

Answer 15

His source.

Answer 16

=_=

Answer 17

Smh

Answer 18

lel bro you didnt do anything all you did was say the exact same thing as me

Answer 19

and that is my work ik the answer

Answer 20

I didn't. I just gave the numbers 2448.

Answer 21

because? I had help on the same question from a student on the site

Answer 22

And you didn't work anything out liar.

Answer 23

yes I did now LEAVE ME ALONE YOU CYBER BULLY THATS ALL YOU DO LITERALLY

Answer 24

Lol imagine not doing your work and lying about doing it

Answer 25

I did my work and I never lied

Answer 26

copy and paste isn't your work