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Mathematics 19 Online
Druskii13:

Help me, please

Druskii13:

Vocaloid:

|dw:1653695496992:dw|

Vocaloid:

1. horizontal (left/right distance). notice on the x-axis, point A is at x = 1, and point B is at x = 4. so the horizontal distance is simply the difference of the x-coordinates, or 4 - 1 = 3 2. calculate the vertical distance using the y-coordinates 3. |dw:1653695617979:dw| if we connect the two points like so and make a right triangle, we can see that the horizontal distance and the vertical distance make up the two legs of a right triangle. the distance between the two points is therefore the hypotenuse. so we can use the pythagorean theorem a^2 + b^2 = c^2, letting a and b be our horizontal and vertical distances, and solve for c, the diagonal distance between the two points

Druskii13:

@vocaloid wrote:
1. horizontal (left/right distance). notice on the x-axis, point A is at x = 1, and point B is at x = 4. so the horizontal distance is simply the difference of the x-coordinates or 4 - 1 = 3 2. calculate the vertical distance using the y-coordinates 3. Created with Raphaƫl1246ABReply Using Drawing if we connect the two points like so and make a right triangle, we can see that the horizontal and vertical distances make up the two legs of a right triangle. the distance between the two points is therefore the hypotenuse. so we can use the Pythagorean theorem a^2 + b^2 = c^2, letting a and b be our horizontal and vertical distances, and solve for c, the diagonal distance between the two points
thank u

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