Question

help

Answer 1

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Answer 2

Okay so \(\sf{x^2 + 4x + 2}\) is in the form,
\(\sf{ax^2+hx+k}\)

We need to get it to \(\sf{a(x-h)^2+k}\)

So first off, let’s identify the numbers that can simply be transferred, \(\sf{a}\) and \(\sf{k}\), we can plug these in

\(\sf{1(x-h)^2+2}\)

Now we need to include \(\sf{h}\), this will require a bit of math

\(\sf{x^2 + 4x + 2}\)

It shows here, that \(\sf{h}\) is 4, but, you can’t just transfer this one, because if you did you would end up with \(\sf{16}\), not \(\sf{4}\) for \(\sf{h}\) (that is because of the square in the new equation), this means we need to find a number that equals \(\sf{4}\) when squared, \(\sf{2}\)

So given that \(\sf{h}\) in the new equation is 2, what would your full new equation be?
( \(\sf{a(x-h)^2+k}\) )