A researcher collected the heights of male seniors at a high school. The data collected are normally distributed with a mean of 70.21 inches and a standard deviation of 1.35. What is the z-score of a high school senior who is 68 inches tall? Enter your answer rounded to the nearest hundredth, like this: 4.23
to calculate the z-score of some value x z-score = (x - x̄)/σ, where x is the value being examined, x̄ is the mean, σ is standard deviation so in your case, x = 68, x̄ = the mean = 70.21, σ = standard deviation = 1.35 plug in the appropriate values, calculate the z-score, and round to the nearest hundredth (2 digits)
Thanks but whats the answer?
The purpose of this website is to teach, rather than to give away answers. Can you try plugging the values into the formula I gave you?
Okay thank you
Do i multiply them together?
the formula I gave you: z-score = (x - x̄)/σ your x-value is 68, your x̄ is 70.21, your σ is 1.35 plugging them in: (68 - 70.21) / (1.35) = ?
-2.9835?
order of operations. 68 - 70.21 = -2.21 -2.21 divided by 1.35 ---> -1.64
-3.277
(68 - 70.21) / (1.35) = -1.64 = your solution
1.34
this is the z-score formula z-score = (x - x̄)/σ you want the z-score of a high schooler who is 68 inches tall, so x = 68 the mean x̄ is 70.21 inches the standard deviation σ is 1.35 when you plug these into the formula, you get (68 - 70.21) / (1.35) = -1.64, that's it, that's your solution.
ooh -1.64 is my solution? Thank you
Nope its the wrong answer
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