You carefully weigh out 14.00 g of CaCO3 powder and add it to 56.70 g of HCl solution. You notice bubbles as a reaction takes place. You then weigh the resulting solution and find that it has a mass of 64.96 g . The relevant equation is

CaCO3(s)+2HCl(aq)→H2O(l)+CO2(g)+CaCl2(aq)

Question

You carefully weigh out 14.00 g of CaCO3 powder and add it to 56.70 g of HCl solution. You notice bubbles as a reaction takes place. You then weigh the resulting solution and find that it has a mass of 64.96 g . The relevant equation is

CaCO3(s)+2HCl(aq)→H2O(l)+CO2(g)+CaCl2(aq)

Narad · Answer

Calculate the number of moles of $$CaCO _{3}$$ and deduce the number of moles of $$CO _{2}$$
Then, calculate the mass of $$CO _{2}$$
Then, you must have the conservation of the mass on both sides of the equation

Naw · Answer

CaCO3 is the limiting reactant in this equation but there is no question you just stated a fact