Simplify (3^4)−1.

one over three raised to the fourth power
one over three raised to the power of negative four
−3^4
3^3

Question

Simplify (3^4)−1.

one over three raised to the fourth power
 one over three raised to the power of negative four
 −3^4
 3^3

Narad · Answer

$$(\frac{ 1 }{ 3 })^{4}=\frac{ 1 }{ 3 ^{4}}$$
$$(\frac{ 1 }{ 3})^{-4}=\frac{ 1 }{ 3^{-4} }$$

Joe348 · Answer

Simplifying (3^4)-1

$$3 \times 3 \times 3 \times 3$$
=$$81$$
$$81-1$$ =
$$80$$

Joe348 · Answer

$$-3^4$$ = $$-3 \times 3 \times 3 \times 3$$
$$=-81$$

$$3^3= 3 \times 3 \times 3 = 27$$

surjithayer · Answer

$$(3^4)^{-1}=3^{(4\times -1)}=3^{-4}=\frac{ 1 }{ 3^4}$$
a

jhonyy9 · Answer

@surjithayer wrote:

$$(3^4)^{-1}=3^{(4\times -1)}=3^{-4}=\frac{ 1 }{ 3^4}$$ a

-1 is exponent sure ?

jhonyy9 · Answer

there is

$$\left( 3^{4} \right)^{-1} = ? $$

or

$$3^{4} -1 = ?$$

Joe348 · Answer

@jhonyy9 wrote:

there is $$\left( 3^{4} \right)^{-1} = ? $$ or $$3^{4} -1 = ?$$

$$(3^4)^-1 = 1/81$$ $$3^4-1=80$$ The second choice is the only correct answer.

Joe348 · Answer

@surjithayer wrote:

$$(3^4)^{-1}=3^{(4\times -1)}=3^{-4}=\frac{ 1 }{ 3^4}$$ a

$$1/3^4=1/81$$ Which is right for that problem, but not for this question.

jhonyy9 · Answer

1 over 3 mean negativ exponent of 3 
and again negativ exponent of 3 not possibile

jhonyy9 · Answer

@joe348 wrote:

@jhonyy9 wrote:

there is $$\left( 3^{4} \right)^{-1} = ? $$ or $$3^{4} -1 = ?$$

$$(3^4)^-1 = 1/81$$ $$3^4-1=80$$ The second choice is the only correct answer.

do you think on this one over three raised to the fourth power ?

Joe348 · Answer

No it would still be 1/81