Question

help plss

Answer 1

Think back to basic arithmetic properties.

For the first statement, the matrix on both sides remains the same, so 4 = (3/4)m and you can solve for m

For the second row, remember addition is commutative. On both sides the problem is equivalent to

H + [1 4 -2] + [3 2 -6] = [-2 3 -1] + [1 4 -2] + [3 2 -6]

Notice that the second and third matrices on both sides are the same so you can cross them out and determine what matrix H is equivalent to.

Finally, calculate m * H

Answer 2

ok my problem is when i put in the numbers i got

[ -7 -112/3 16/3]

is this the correct order?

Answer 3

I got something a little different

4 = (3/4)m, making m = 16/3

H = [-2, 3, -1]

m*H is therefore [-32/3 , 16 , -16/3]

Answer 4

can you please explain how you got that?

Answer 5

4 * matrix = (3/4)m * that same matrix

So 4 must equal (3/4)m which lets you solve for m

For the second statement, H + matrix 2 + matrix 3 = matrix 1 + matrix 2 + matrix 3, so if you subtract matrix 2 and 3 from both sides you get H = matrix 1

H = [-2, 3, -1]

Then simply multiply m * H

Answer 6

when you multiply m*H

you mean 16/3 * every number in the matrices?

Answer 7

ok thank you i get it now