Question

HELP PLEASE

Answer 1

please please help

Answer 2

So what you wanted to do here is use the rule of `a power in a power`, which is this:

\(\sf\color{gray}{\text{If a base is raised to a power that is then raised to another power} \\ \text{you multiply the two powers together}}\)

Using this rule, you use the -2 power associated on the outside of the parenthesis and multiply every power inside of it by -2.

Answer 3

okay i don't really understand that i have to do this quickly

Answer 4

i'll just do it tomorrow :|

Answer 5

????????

Answer 6

With what?

Answer 7

use this

\[x^{-2} = \frac{ 1 }{ x^{2} }\]

Answer 8

Here, I'll draw up the equations

\(\color{gray}{\sf{\huge{(}}\dfrac{y^{-2}z^3}{z^{-4}y^5}{\huge{)^{-2}}}}\)

That's what it normally looks like, but this is what the -2 does
\(\color{gray}{\sf{\huge{(}}\dfrac{y^{4}z^{-6}}{z^{8}y^{-10}}{\huge{)}}}\)

Now from that, you can divide both of them, using the rule of power division, which is below
\(\sf{\color{gray}{\text{If an exponent with the same base variable is divided by a similar variable, } \\ \text{the exponent of the numerator is subtracted by the exponent of the denominator.}}}\)

This would give you
\(\sf\color{gray}{y^{(4)-(-10)} z^{(-6)-(8)}}\)

Answer 9

Whoops sorry jhonyy, didn't see you typing

Answer 10

yes thank you very much both