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Mathematics 9 Online
Strawberrys:

Write an equivalent expression by distributing the "-−" sign outside the parentheses: -(0.1k+2)

Frosted:

Okay, when distributing the negative to each number, it looks like this: |dw:1663850863900:dw| So now looking at this, what needs to be done?

Strawberrys:

yes ik that

Frosted:

So what exactly can I help you with?

Strawberrys:

im just bamboozled

Frosted:

So do you know what a negative x a postive is?

Strawberrys:

a neg

Strawberrys:

ofc

Frosted:

Yes, so a: \[-1 \times0.1k=?\]

Strawberrys:

-0.1k right

Frosted:

Correct! Now, \[-1 \times 2=?\]

Strawberrys:

-2

Frosted:

Nice! So your final answer will look like?

Strawberrys:

-0.1k+-2

Strawberrys:

correct

Frosted:

You don't need the addition sign in there, but yes!

Strawberrys:

thx for the help!!!

Frosted:

No problem! If you ever need my help, just let me know!

Strawberrys:

i have another one

Frosted:

Okay, I can assist you with that.

Strawberrys:

its in the dms

Frosted:

So you sent me a DM with this equation.: \[−(3u+8.2)\] Now, you should distribute as you did before. \[-1\times3u=?\] and \[-1\times8.2=?\] Then let me know your final answer!

Strawberrys:

-3u and -8.2

Frosted:

Perfect, now put it in the equation it was in before.

Strawberrys:

-3u-8.2

Frosted:

Correct! Good Work! =)

Strawberrys:

thank you i think i get it

Frosted:

I'm glad you do! Again, in case you have another problem, I'll be right here.

Strawberrys:

one more

Frosted:

Alright, let me know.

Strawberrys:

-(5n+5.8p)-7 −(5n+5.8p)−7

Frosted:

Alright so now we have a number outside the parenthesis, correct?

Strawberrys:

yes it is a -1

Strawberrys:

right

Frosted:

Yes, and no. There is a -7, so we can leave that out for now.

Strawberrys:

what i got was -5n-5.8p-7

Frosted:

So let's distrubute the -1 as normal to: \[-1\times 5n=?\] and \[-1\times5.8p=?\]

Strawberrys:

it is in my last comment

Frosted:

Yes, that is correct, Strawberrys!

Strawberrys:

thx

Frosted:

Of course!

Strawberrys:

ur rlly smart

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