Question

✨Chem help ✨

Find the appropriate pressure of 2 helium in a 0.3m^3 container at 300k.


I'll show below what my teacher showed us to do but I forgot the next step and am struggling x.x

Answer 1

\[P(.3^3)=(2 moles)(8.314)^3(300k)\]

He told us to cross out moles (2 moles (aka 2 Helium), and k in 300k.

Answer 2

He told us we should know what to do next but I'm kind of struggling with that because we've done the problem but it was a different equation with different strategies.

I've rewatched his lecture on it but I still can't quite understand.

Answer 3

The volume is 0.3 m^3. The exponent 3 applies to the unit not the quantity 0.3. Also the ideal gas constant is simply 8.314 J/molK not 8.314^3

P(0.3 m^3) = (2 moles)(8.314 J/molK)(300K).

You’d treat it like any other equation and solve for P. Multiply 2 * 8.314 * 300 on the right side and divide by 0.3 to isolate P.

Answer 4

Nvm your pressure should be in kPa after cancelling out units.