Question

geometry help!

Answer 1

@hero

Answer 2

@jhonyy9

Answer 3

@dude

Answer 4

Am i right with C? or is it D?

Answer 5

Sorry for the very long wait!


\(\sf{-~-~-~-~-~-~-~-~-~-~}\)


So if you look at the figure provided, you can see that \(\sf{\angle BAE}\) is half of \(\sf{\angle BAD}\).

This being given, you can make a solve-for-x equation using the angle of \(\sf{\angle BAD}\) equal to the angle of \(\sf{\angle BAE}\).


\(\sf{\dfrac{130}{2} = 9x + 2}\)
\(\sf{\,~~~65 = 9x + 2}\)

Now you can just solve for \(\sf{x}\) and get what your x value would be.


\(\sf{-~-~-~-~-~-~-~-~-~-~}\)


Best of luck,
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text-shadow: 2px 2px 3px white, 0 0 10px white, 0 0 5px white;color:#23B7F3;font-size:100px;padding:50px;width:500px;height:100%;position:absolute;left:0;z-index:500;text-align:center;} {\Huge\sf\color {} {{-~Akuma~matata}}}\)
"what a wonderful phrase"

Answer 6

really need help w one more if u can

Answer 7

No problem!

Answer 8

Make a new post

Answer 9

alright.