Question

A braking car on dry pavement has a constant acceleration of −6.0 m/s2. If the car was moving at 10.0 m/s, approximately how long would it take it to stop?

Answer 1

kinematics equation: vf = vi + at
where vf is the final velocity, vi is the inital velocity, a is the acceleration, and t is time. since the car is coming to a stop, the vf is 0. the car starts at 10.0 m/s so vi = 10.0. acceleration is given as a = -6.0 m/s^2. plug in the appropriate quantities and solve for t.