Question

I need help with this: The acceleration due to gravity is 14.07m/s2. If a space rock initially falling at 30.00m/s continues to fall, how far would it fall in the next 35.00 seconds

Answer 1

Using one of the kinematics equations

Delta x = v0*t + (1/2)at^2

Where delta x is the distance travelled, v0 is the initial velocity (30.0 m/s), a is the acceleration (14.07 m/s^2), t is time (35.00 seconds). Plug in the appropriate quantities and evaluate delta x.

Answer 2

(30.0 m/s) times (35.00 seconds)+(1/2)(14.07 m/s^2)(35.00 seconds)^2?

Answer 3

Yes

Answer 4

Hey can you help me with my other one

Answer 5

Wait so the final answer is 9667.875?