What single transformation maps ∆ABC onto ∆A'B'C'? Graph shows 2 triangles plotted on a coordinate plane. Triangle 1 is at A(minus 3, 1), B(minus 1, 2), C(minus 2, 1). Triangle 2 is at A prime (minus 1, minus 3), B prime (minus 2, minus 1), C prime (minus 1, minus 2). A. rotation 90° clockwise about the origin B. rotation 90° counterclockwise about the origin C. reflection across the x-axis D. reflection across the line y = x
any idea ? but please explain it
all your's math professor history is my skill
to get from AC the A'C' what you need to do ?
translation up 4 units, followed by rotation CCW by 90°.
its 10th grade math and idk
good thing my google dock still got those answers and questions
ok can this be reflection ?
rotate CCW by 90 again followed by 4 rotations to the left
rotate to the left so what mean this ? what option from these two ?
A. rotation 90° clockwise about the origin B. rotation 90° counterclockwise about the origin C. reflection across the x-axis D. reflection across the line y = x these r the answer choose
courage this is easy now
A or B ?
A
than you rotate this triangle about the origin clockwise 90° where will get the resulted triangle ,in what quadrant ?
in quadrant 1 not in 3
@tyrun ok ? who asked it is off line
question ?
wht
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