There are 8 players on a tennis team. The team is planning to play in a doubles tournament. How many different groups of players of 2 players can the coach make, if the position does not matter?

A. 28
B. 64
C. 20,160
D. 40,320

Question

There are 8 players on a tennis team. The team is planning to play in a doubles tournament. How many different groups of players of 2 players can the coach make, if the position does not matter?

A. 28
B. 64
C. 20,160
D. 40,320

Arieonna · Answer

i got 20,160 as my answer

Arieonna · Answer

i will bring my explanation in a minute

Arieonna · Answer

Using the arrangements formula, it is found that there are 20,160 different groups of players of 2 players that the coach can make.

What is the arrangements formula?
The number of possible arrangements of n elements is given by the factorial of n, that is:

In this problem, all 8 players will play, hence considering the order, the number of ways is:

40,320/2 = 20,160.

Arieonna · Answer

you can loom up the answer on brainly.com

carmelle · Answer

lol u copied it straight from brainly, but that's okay, I figured out the answer already. thanks for the effort though! :)

Arieonna · Answer

i am still trying to figure out my history problem i am having trouble on at the very top of the question center it is History i really need help on  it

carmelle · Answer

The answer is actually A. 28.

Here's what I did, using the combination formula:
$$\frac{ 8! }{ 2! \div 6! } = 28$$

carmelle · Answer

@carmelle wrote:

The answer is actually A. 28. Here's what I did, using the combination formula: $$\frac{ 8! }{ 2! \div 6! } = 28$$

my bad, I meant: $$\frac{ 8! }{ 2! \times 6! } = 28$$