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The question is in the comments - algebra 2
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\[3^{x-4} = 6\] take the log base 3 on each side \[\log_{3}(3^{x-4})=\log_3{6}\] log_3 (3) cancels out \[x-4=\log_3{6}\] apply the change of base formula to the log on the right. the "y" value will be 6 and the base "b" will be 3. from there, simply divide the two logs, then add 4 to both sides to isolate x.
Okay, thank you so much, I think I understand now! Did I solve it correctly? \[x - 4 =\frac{ \log(6) }{ \log(3) }\] \[x - 4 = \frac{ 0.778151 }{ 0.477121 }\] \[x - 4 = 1.630930\] \[x = 5.630930\]
Correct, just make sure to round to the thousandth place (3 decimal places)
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