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Mathematics 11 Online
Lala15:

i need help with this math

Lala15:

-10(2-6v)

ShadowOfDeath:

How we do this one is quite simple. What we use is something called the distributive property. For example, let's take the problem you have now. We would "distribute" the -10 to both of the terms in the parenthesis. Once you do that, the final product is a prime equation, so it's impossible to simplify. Therefore, your final answer is what you would get when you distribute -10 to the 2 and the 6v.

Isaacccc:

Idk🌚

jhonyy9:

@shadowofdeath wrote:
How we do this one is quite simple. What we use is something called the distributive property. For example, let's take the problem you have now. We would "distribute" the -10 to both of the terms in the parenthesis. Once you do that, the final product is a prime equation, so it's impossible to simplify. Therefore, your final answer is what you would get when you distribute -10 to the 2 and the 6v.
Attention ! -6v not 6v

ShadowOfDeath:

Oh. Thank you! I didn't notice that.

Kaylee013:

the answer would be around 60v-20 if i did the math right

minionslover:

idk

bluebonnets:

60v-20 you would just distribute the -10 to the 2 and -6, and since a negative multiplied by a negative makes a positive then you would get 60

miazzzzlife:

in short the answer is 60v-20

Joe348:

In simpler words and explanations without giving a direct answer You would distribute the -10 to both of the numbers 2 and -6 v \[-10 \times 2 \] \[-10 \times -6v\] \[-10 \times 2 =-20\] \[-10 \times -6v = 60v\] Final answer : \[60v-20\]

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