A school received a shipment of alg and geometry books costing $4200. The cost of 1 alg book is $12, and one geometry book is $15. If there are 124 more alg books than geometry books, how many of each kind of math book were in the shipment?
@dude
let a = the number of algebra books and g = the number of geometry books if each algebra book costs $12, then the cost of (a) algebra books is 12*a or simply 12a. similar logic with the geometry books (15g) the total cost of the algebra and geometry books is $4200 so equation 1: 12a + 15g = 4200 there are 124 more alg books than geometry books, so equation 2: a = g + 124 you now have two equations which you can use to solve for two unknowns. you can plug the second equation back into the first equation to get the first equation in terms of g only. solve it for g. from there, you can go back and plug g into the second equation to solve for a.
Join our real-time social learning platform and learn together with your friends!