ALGEBRA 2:Solve the following system of equations and show all work. y = −x2 + 4 y = 2x + 1
the ordered pairs are (-3, -5) and (1, 3).
x=1 or x=-3 y=3 y=-5
you there
? how do you do it?
oh ok sorry
How do you solve it
i will come back with the steps ok
Alright thank you
do you mean x^2
thats impossible
to slove
trust me i know
I just mean how do you solve it step for step I want to learn and i need to solve it. And i do you know?
y=-x2 + 4, y=2x+1 Solution: y = -x2 + 4 y = 2x + 1 These linear equations can be solved by using elimination or substitution method As both the equations are equal to y, the two equations are equal to one another. -x2 + 4 = 2x + 1 By further calculation 4 - 1 = 2x + x2 It can be written as x2 + 2x = 3 x2 + 2x - 3 = 0 (x + 3) (x - 1) = 0 So we get x = -3 or 1 Substituting the value of x in either of the equations y = 2x + 1 or y = 2x + 1 y = 2 (-3) + 1 or y = 2 (1) + 1 y = - 6 + 1 or y = 2 + 1 y = -5 or y = 3 Therefore, the ordered pairs are (-3, -5) and (1, 3). Solve the following system of equations and show all work. Summary: Solving the following system of equations, the ordered pairs are (-3, -5) and (1, 3).
sorry
me neither. So what are the steps bryan?
here you go
y=-x2 + 4, y=2x+1 Solution: y = -x2 + 4 y = 2x + 1 These linear equations can be solved by using elimination or substitution method As both the equations are equal to y, the two equations are equal to one another. -x2 + 4 = 2x + 1 By further calculation 4 - 1 = 2x + x2 It can be written as x2 + 2x = 3 x2 + 2x - 3 = 0 (x + 3) (x - 1) = 0 So we get x = -3 or 1 Substituting the value of x in either of the equations y = 2x + 1 or y = 2x + 1 y = 2 (-3) + 1 or y = 2 (1) + 1 y = - 6 + 1 or y = 2 + 1 y = -5 or y = 3 Therefore, the ordered pairs are (-3, -5) and (1, 3). Solve the following system of equations and show all work. Summary: Solving the following system of equations, the ordered pairs are (-3, -5) and (1, 3).
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