Question

help with physics

Answer 1

Idk F = ma is on the side. It looks like you can input answers into it, but there's no acceleration (change in velocity) happening so I'm not sure why they have that there.

Answer 2

they put it there to mess us up

Answer 3

Anyway, the bicyclist is creating a forward force of 150N. There is 40N drag which is an oppositional force to that forward force.

Answer 4

would n be 0 because hes not going up

Answer 5

It's not that he isn't going up, but that there's no force pushing him up.

Answer 6

yes so it would be 0 then?

Answer 7

Correct

Answer 8

bro what i put 0 and it said it was wrong?

Answer 9

nvm that

Answer 10

I mean technically his weight is pushing down, then the ground is pushing up.

Answer 11

this is destroying my brain i should have never took this class idek why they put me in here

Answer 12

Yeah it sounds like you weren't briefed on Newton's Laws

Answer 13

all ik is what goes up must come down

Answer 14

Basically Newton's Third law is that everything has an equal and opposite force. If you punch a wall, it punches back. When you walk, gravity is pulling you down, but when you make contact with the earth, it pushes you back up. So technically you can do F = 65(gravity) then solve for the downward force, then just write the same value for the upward force but no negative sign

Answer 15

thanks shadow your the best

Answer 16

idk how many decimal points your school wants but -9.8 m/s^2 is what some ppl do for the value of gravity.

But on the vertical access, the net force (Fn) would be zero. But in the horizontal axis, obviously you'll have to subtract the drag from the forward force.