Question

A train starts from grande city in travels to Belleville 388 miles away. At the same time a train starts from Belleville rooms at the rate of 47 mph tour grande city they passed each other four hours later find the rate of the train from Grand Cit.y

Answer 1

In general, distance = speed * time

For the train from Grand City, it travels some unknown distance d, with unknown speed (x), in 4 hours (t = 4).

So for the Grand train, d = 4x

The total distance between the cities is 388 miles. So when the two trains meet, if one train has driven d distance, the other one must have travelled 388 - d distance.

So the Belleville train travels 388 - d. It’s speed is 47 mph and the time is also 4 hrs since it left at the same time. So using the same distance = speed * time equation, 388 - d = 47(4)

Solve this equation for d. From there you can plug the d-value back into the Grand City equation and solve for the rate x.

Answer 2

We can use the formula:

distance = rate x time

Let's call the rate of the train from Grand City "R".

The first train travels for 4 hours at the rate of R mph, so it travels a distance of 4R miles.

The second train travels for 4 hours at the rate of 47 mph, so it travels a distance of 4 x 47 = 188 miles.

Since the two trains start at opposite ends of the 388-mile distance between the two cities and pass each other, the total distance they travel together is 388 miles.

Therefore, we can set up the equation:

4R + 188 = 388

Solving for R:

4R = 200

R = 50

So the rate of the train from Grand City is what.