@vocaloid can you give some steps on how to do this
Vocaloid:
there are some mistakes in the points you've plotted. (-5,3) and (-3,3) are in quadrant II.
|dw:1680304075347:dw|
this will make a rectangle, which, as you've demonstrated in previous problem, will make a cylinder when rotated about the x-axis.
Vocaloid:
|dw:1680304200792:dw|
should be straightforward to calculate the appropriate lengths from here
Gucchi:
wait so would the height be 2 and diameter 3?
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Vocaloid:
notice how the x-axis goes along the diameter of the cylinder.
consider one of the circles as the base of the cylinder. I'll use the right one as an example. the center of the circle is (-3,0). the circle's radius extends from (-3,0) to (-3,3) which has a distance of 3 points. (3 - 0 = 3). double that to get the diameter, 6.
the height is 2 as you have correctly stated (5-3=2).
Gucchi:
@vocaloid wrote:
there are some mistakes in the points you've plotted. (-5,3) and (-3,3) are in quadrant II.
Created with Raphaƫl(-5,3)(-3,3)(-5,0)(-3,0)Reply Using Drawing
this will make a rectangle, which, as you've demonstrated in previous problem, will make a cylinder when rotated about the x-axis.
im so dumb lol i didnt see this
Vocaloid:
|dw:1680305102521:dw|
Gucchi:
@vocaloid wrote:
notice how the x-axis goes along the diameter of the cylinder.
consider one of the circles as the base of the cylinder. I'll use the right one as an example. the center of the circle is (-3,0). the circle's radius extends from (-3,0) to (-3,3) which has a distance of 3 points. (3 - 0 = 3). double that to get the diameter, 6.
the height is 2 as you have correctly stated (5-3=2).