Question

More math: https://snipboard.io/WMLxr8.jpg
Options: https://snipboard.io/iQ3gRN.jpg

Answer 1

\[\sin \theta =-\frac{ 6 }{ 15 }\]
\[\cos \theta=-\frac{ \sqrt{189} }{ 15}\]
\[\sin 2\theta =2\sin \theta \cos \theta \]

Answer 2

So out of these four options
A. 12(√133)/169

B. 4(√189)/75

C. 12/225

D. -√189/169
what would be the exact value of sin2θ=2sinθcosθ?

Answer 3

@surjithayer

Answer 4

\[OM=-\sqrt{OP^2-OM^2}=-\sqrt{(15)^2-(-6)^2}=-\sqrt{225-36}=-\sqrt{189}\]
\[\cos \theta=\frac{ OM }{ OP }=\frac{ -\sqrt{189} }{ 15 }\]
\[\sin \theta=\frac{ -6 }{15 }\]
\[\sin 2\theta=2\sin \theta \cos \theta=2\times ?\times?=?\]
substitute the values and find the solution.

Answer 5

\[\sin 2\theta=2\sin \theta \cos \theta=2\times \frac{ -6 }{ 15 }\times \frac{ -\sqrt{189} }{ 15}=\frac{ 4\sqrt{189} }{ 75 }\]

Answer 6

Omg all I had to do is plug that in to get the answer, smh but thanks!