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So if the equation is \(b=\dfrac{3}{4}h\) and he makes 6 bouquets, your equation would be. \(6=\dfrac{3}{4}h\) Now you need to solve for \(h\), the easiest way would be to flip the fraction and multiply both sides by it. \(\dfrac{4}{3}\times6=(\dfrac{3}{4}h)\times\dfrac{4}{3}\) Which cancels out the \(\dfrac{3}{4}\). \(8=h\) So it would take him \(8\) hours to make \(6\) bouquets.
@extrinix wrote:
So if the equation is \(b=\dfrac{3}{4}h\) and he makes 6 bouquets, your equation would be.
\(6=\dfrac{3}{4}h\)
Now you need to solve for \(h\), the easiest way would be to flip the fraction and multiply both sides by it.
\(\dfrac{4}{3}\times6=(\dfrac{3}{4}h)\times\dfrac{4}{3}\)
Which cancels out the \(\dfrac{3}{4}\).
\(8=h\)
So it would take him \(8\) hours to make \(6\) bouquets.
Of course
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