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Gucchi:
@timmyspu
Gucchi:
@hero
Hero:
@Gucchi check messages
Gucchi:
@joe348
cjmick26:
sorry bud i cant with geometry
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Maya12:
@oliver69
Maya12:
@maya12 wrote:
@oliver69
HES THE SMART ONE
OLIVER69:
Actually, @gucchi I just went over and checked each part to make sure that it is completed correctly. And it is completed correctly. You should get a great grade on this. I see no mistakes and you no longer need help on this.
Gucchi:
@oliver69 wrote:
Actually, @gucchi I just went over and checked each part to make sure that it is completed correctly. And it is completed correctly. You should get a great grade on this. I see no mistakes and you no longer need help on this.
u sure?
OLIVER69:
@gucchi wrote:
@oliver69 wrote:
Actually, @gucchi I just went over and checked each part to make sure that it is completed correctly. And it is completed correctly. You should get a great grade on this. I see no mistakes and you no longer need help on this.
u sure?
yes, I am sure... also you shouldn't second-guess yourself... but I am 100% sure it's correct
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Gucchi:
@oliver69 wrote:
@gucchi wrote:
@oliver69 wrote:
Actually, @gucchi I just went over and checked each part to make sure that it is completed correctly. And it is completed correctly. You should get a great grade on this. I see no mistakes and you no longer need help on this.
u sure?
yes, I am sure... also you shouldn't second-guess yourself... but I am 100% sure it's correct
yeah ik man i always second guess to make sure
Gucchi:
how did u check it tho jus curious
OLIVER69:
Well, I went over each part, and for part 1, I made sure that the radius was less than 10 because of the radius from the (0,0) coordinate. As for part two I made sure I knew the equation for the circle which is (x)^2 + (y)^2 = r^2
And since then the radius was 5 then it would be equal to 25.
As for part three, it said the main power connection needed to be on the outside, so the point that was chosen was -5.5 it would be correct, or really any point you chose on the y-intercept.
As for part four, you considered all the elements you needed on the graph.
(I hope this makes sense)
idfkaa:
bro was not playing
Gucchi:
@oliver69 wrote:
Well, I went over each part, and for part 1, I made sure that the radius was less than 10 because of the radius from the (0,0) coordinate. As for part two I made sure I knew the equation for the circle which is (x)^2 + (y)^2 = r^2
And since then the radius was 5 then it would be equal to 25.
As for part three, it said the main power connection needed to be on the outside, so the point that was chosen was -5.5 it would be correct, or really any point you chose on the y-intercept.
As for part four, you considered all the elements you needed on the graph.
(I hope this makes sense)
thank you
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Gucchi:
@oliver69 wrote:
Well, I went over each part, and for part 1, I made sure that the radius was less than 10 because of the radius from the (0,0) coordinate. As for part two I made sure I knew the equation for the circle which is (x)^2 + (y)^2 = r^2
And since then the radius was 5 then it would be equal to 25.
As for part three, it said the main power connection needed to be on the outside, so the point that was chosen was -5.5 it would be correct, or really any point you chose on the y-intercept.
As for part four, you considered all the elements you needed on the graph.
(I hope this makes sense)
so i could choose any point on the y intercept?
Gucchi:
so i couldve done like -5, 7 or something right
OLIVER69:
@gucchi wrote:
so i couldve done like -5, 7 or something right
I meant any point on the y-axis so you could have chose really anything from 1 - 9 on the y - axis
Gucchi:
so like -5, 7 would be one right
Gucchi:
im just curious
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OLIVER69:
based on the graph (-5, 7) wouldn't be one, but (-4, -2.5) would be one
Gucchi:
@oliver69 wrote:
based on the graph (-5, 7) wouldn't be one, but (-4, -2.5) would be one
ok perfect srry for bothering u again but how can i make this graph on geogebra
Okay I think I figured out how to graph the tangent line on the graph, I didn't put the circle on there, but I did do the line. I hope it looks correct...
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Gucchi:
@oliver69 wrote:
@gucchi wrote:
@oliver69 wrote:
That looks good as to the original picture you did. I think you have completed the assignment. Good Job.
theres actually 1 more step to the assignment i jus found out lol
Oh what is it and do you need help
can you please guide me for this one
OLIVER69:
@gucchi wrote:
@oliver69 wrote:
@gucchi wrote:
@oliver69 wrote:
That looks good as to the original picture you did. I think you have completed the assignment. Good Job.
theres actually 1 more step to the assignment i jus found out lol
Oh what is it and do you need help
can you please guide me for this one
yes of course
OLIVER69:
Okay so for number 5 it's fairly easy you just need to decide the new points for the radius and the center. To make that easy, I would suggest you make the center on the x-axis... for example (5,0) would be good and as for the radius, you would need to come up with a rubber that is halfway across from the center, so for example a radius of 6 would be nice because the diameter would be 12, a nice even number. Makes sense?
OLIVER69:
As for number six, you would describe how it moved rather it moved up, down, left or right and for the example center I gave it would have moved right 5. As to determine the scale factor it would be the ratio between the old and new stages. For the example radius I gave the scale factor would be 5:6. Makes sense?
Gucchi:
okayy question tho do i need to make another graph of this one liike the one i just did
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Gucchi:
on geogebra
OLIVER69:
@gucchi wrote:
okayy question tho do i need to make another graph of this one liike the one i just did
yes you would need to
Gucchi:
@oliver69 wrote:
@gucchi wrote:
okayy question tho do i need to make another graph of this one liike the one i just did
yes you would need to
k do i put one for question 5 and 6 or only 6 srry bout these questions
OLIVER69:
Only 5 because it wants you to graph it there and then off to the side of the graph describe it.
Gucchi:
@oliver69 wrote:
Okay so for number 5 it's fairly easy you just need to decide the new points for the radius and the center. To make that easy, I would suggest you make the center on the x-axis... for example (5,0) would be good and as for the radius, you would need to come up with a rubber that is halfway across from the center, so for example a radius of 6 would be nice because the diameter would be 12, a nice even number. Makes sense?
Gucchi:
Hero:
cjmick26:
Maya12:
OLIVER69:
idfkaa:
Addif9911:
Him I dimmed the light that once felt mine, a glow I never meant to lose. I over-read the shadows, let voices crowd the room where only two hearts shouldu20
EdwinJsHispanic:
Poem to my mom who proved my point "You proved my point, I am a failure. but I kinda wish, you were my savior.
Wolfwoods:
The Modern Princess "you spoke so softly to me, held me close when no one else did, loved me in a way no one else dared to.
notmeta:
balance the following equation - alumoinum chlorate --> alumninum chloride + oxyg