Question

A 500.0 kg pig is standing at the top of a muddy hill on a rainy day. The hill
is 100.0 m long with a vertical drop of 30.0 m. The pig slips and begins to
slide down the hill. What is the pig’s speed at the bottom of the hill?

Answer 1

Potential Energy at the top of the hill = Kinetic Energy at the bottom of the hill
\[mgh=\frac{ 1 }{ 2 }m v^{2}\]
\[v=\sqrt{2gh}\]
where h is the height of the hill