Question

Math: https://snipboard.io/EpFUyn.jpg

Answer 1

Its not option D.) which is V

Answer 2

I was thinking Q

Answer 3

@surjithayer

Answer 4

Which of the following represents the polar equation r = (cot 2θ)(csc θ) as a rectangular equation?

x2 + y2 = 1
y = 1
y2 = x3
y3 = x2

Answer 5

Its either y2 = x3 or y3 = x2

Answer 6

\[r \sin \theta=\frac{ \cos 2\theta }{ \sin 2\theta }\]
\[y=\frac{ \cos ^2\theta-\sin ^2\theta }{ 2\sin \theta \cos \theta }=\frac{ r^2\cos ^2\theta-r^2\sin ^2\theta }{ 2(r \sin \theta)(r \cos \theta)}=\frac{ x^2-y^2 }{ 2xy }\]
\[2xy^2=x^2-y^2,x^2=(2x+1)y^2,y^2=\frac{ x^2 }{ 2x+1}\]
no option matches this answer.
if question is \[r=\cot ^2\theta \csc \theta \]
\[r \sin \theta=\frac{ \cos ^2\theta }{ \sin ^2\theta }=\frac{ r^2\cos ^2\theta }{ r^2\sin ^2\theta }\]
\[y=\frac{ x^2 }{ y^2 },y^3=x^2\]