Question

9/10

Answer 1

@luigi0210

Answer 2

I would start with solving for x:
\[\large y-x=4 \]
\[\large x= y-4 \]
and substitute that into the second
\[\large 6y+2(y-4)=4 \]
Simplify
\[\large 6y +2y-8 =4 \]
\[\large 8y = 12 \]
Giving you y:
\[\large y= \frac{3}{2} \]

Now you can plug that into y

Answer 3

\[\large x= \frac{3}{2}-4 \]

giving you
\[\large x= -\frac{5}{2} \]

So as an ordered pair
\[\large (-\frac{5}{2}, \frac{3}{2} )\]