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NickCobies · Answer

1. What is the limit as x approaches 0 of (sin x) / x?

Yaz2poppin · Answer

the limit of sin(θ)/θ as θ approaches 0 is equal to 1. We use a geometric construction involving a unit circle triangles  and trigonometric functions. By comparing the areas of these triangles and applying the squeeze theorem we demonstrate that the limit is indeed 1.

NickCobies · Answer

@yaz2poppin wrote:

the limit of sin(θ)/θ as θ approaches 0 is equal to 1. We use a geometric construction involving a unit circle triangles and trigonometric functions. By comparing the areas of these triangles and applying the squeeze theorem we demonstrate that the limit is indeed 1.

Thank you Yazlyn it was corect

Extrinix · Answer

If it is approaching a certain number, you replace $x$ with the given number (in this case, $0$).

That would be $\dfrac{sin(0)}{0}$

If you evaluate that, you'll see that the $sin(0)$ simply equals zero.

That would make your equation: $\dfrac{0}{0}$

Knowing that a trig function can never equal zero, your answer would be $undefined$.

Yaz2poppin · Answer

ofc

@nickcobies wrote:

@yaz2poppin wrote:

the limit of sin(θ)/θ as θ approaches 0 is equal to 1. We use a geometric construction involving a unit circle triangles and trigonometric functions. By comparing the areas of these triangles and applying the squeeze theorem we demonstrate that the limit is indeed 1.

Thank you Yazlyn it was corect

ofc

JESUS4EveR · Answer

@yourroyalfinestt wrote:

@jesus4ever wrote:

@yourroyalfinestt wrote:

ya its one

copycat

bruh aint no way u mad bc we all got the same answer

I answered first. You merely copied.

NickCobies · Answer

@extrinix wrote:

If it is approaching a certain number, you replace $x$ with the given number (in this case, $0$). That would be $\dfrac{sin(0)}{0}$ If you evaluate that, you'll see that the $sin(0)$ simply equals zero. That would make your equation: $\dfrac{0}{0}$ Knowing that a trig function can never equal zero, your answer would be $undefined$.

But it says it Is 1 ?

JESUS4EveR · Answer

@jesus4ever wrote:

@yourroyalfinestt wrote:

@jesus4ever wrote:

@yourroyalfinestt wrote:

ya its one

copycat

bruh aint no way u mad bc we all got the same answer

I answered first. You merely copied.

And you ain't no royal finest!

Yaz2poppin · Answer

ok can we all stop now lol

Yaz2poppin · Answer

.

xXDerpyPugXx · Answer

Salsa is crazyy

Yaz2poppin · Answer

LMAO

Extrinix · Answer

@nickcobies wrote:

@extrinix wrote:

If it is approaching a certain number, you replace $x$ with the given number (in this case, $0$). That would be $\dfrac{sin(0)}{0}$ If you evaluate that, you'll see that the $sin(0)$ simply equals zero. That would make your equation: $\dfrac{0}{0}$ Knowing that a trig function can never equal zero, your answer would be $undefined$.

But it says it Is 1 ?

Undefined is one, in most cases

NickCobies · Answer

@extrinix wrote:

@nickcobies wrote:

@extrinix wrote:

If it is approaching a certain number, you replace $x$ with the given number (in this case, $0$). That would be $\dfrac{sin(0)}{0}$ If you evaluate that, you'll see that the $sin(0)$ simply equals zero. That would make your equation: $\dfrac{0}{0}$ Knowing that a trig function can never equal zero, your answer would be $undefined$.

But it says it Is 1 ?

Undefined is one, in most cases

Ohhh that would make sense I should have included answer choices my bad "undefined" wasnt an opton

NickCobies · Answer

Thank u guys!