Question

Ok so I'm on this math problem and I need help its 2/16× × =18/32

Answer 1

So you're going to want to do 2 over 16(18 over 32 heres how I did it. But I think you have to simplify

Answer 2

Ok ty that helped

Answer 3

Yes

Answer 4

I don't feel like Tbone's response is what you were looking for... So I'll try my best to answer this.

Answer 5

Given: \[\frac{ 2 }{ 16 } \times x\]
\[x = \frac{ 18 }{ 32 }\]

It would look like this: \[\frac{ 2 }{ 16 }\left(\begin{matrix}18 \\ 32\end{matrix}\right)\]

Now, if you apply the rule of \[(a)=a\] It would look like this:
\[\left(\begin{matrix}18 \\ 32\end{matrix}\right) = \frac{ 18 }{ 32 }\]
So therefore for part 1, it'd completely look like this:\[= \frac{ 2 }{ 16 } \times \frac{ 18 }{ 32 }\]
Now, you'd just need to cancel the numbers: \[\frac{ 2 }{ 16 } = \frac{ 1 }{ 8 }\]
\[\frac{ 1 }{ 8 } \times \frac{ 18 }{ 32 }\]
In order to do that, we use factoring, which will look like this on the second fraction: \[\frac{ 18 }{ 32 } = \frac{ 9 }{ 16 }\]
Factoring: \[18=2\times9\]
\[=\frac{ 2\times9 }{ 32 }\]
Factoring continued:\[32=2\times 16\]
\[=\frac{ 2\times9 }{ 2\times16 }\]
*Canceling the common factor: 2
\[=\frac{ 9 }{ 16 }\]\[=\frac{ 1 }{ 8 }\times \frac{ 9 }{ 16 }\]
Applying the fraction rule; example: \[\frac{ a }{ b} \times \frac{ c }{ d }=\frac{ a \times c }{ b \times d }\]
With our problem:
\[=\frac{ 1 \times 9 }{ 8 \times 16}\]
Multiplication:
\[1 \times 9 = 9\]
\[8 \times 16 = 128\]
Which leaves you with your final answer:
\[=\frac{ 9 }{ 128 }\]

*For such terms as canceling for fractions, it's basically dividing a smaller number for both the top number and bottom number which is our common factor. Here's an example \[\frac{ 3 }{ 9 } = \frac{ 1 }{ 3 }\]
Which leads 3 to be your common factor.


Hope this has helped, and good luck! (: