Question

You have three molecules of sodium bicarbonate 3NaHCO3.

Which statement is true?
Responses

The number of sodium atoms (Na) is greater than the number of hydrogen atoms (H).
The number of sodium atoms , left parenthesis uppercase N lowercase a right parenthesis, is greater than the number of hydrogen atoms , left parenthesis uppercase H right parenthesis, .
The number of oxygen atoms (O) is less than the sum of the sodium (Na), hydrogen (H), and carbon (C) atoms.
The number of oxygen atoms , left parenthesis uppercase O right parenthesis, is less than the sum of the sodium , left parenthesis uppercase N lowercase a right parenthesis, , hydrogen , left parenthesis uppercase H right parenthesis, , and carbon , left parenthesis uppercase C right parenthesis, atoms.
The number of carbon atoms (C) is three times greater than the number of oxygen atoms (O).
The number of carbon atoms , left parenthesis uppercase C right parenthesis, is three times greater than the number of oxygen atoms , left parenthesis uppercase O right parenthesis, .
The number of oxygen atoms (O) equals the sum of the sodium (Na), hydrogen (H), and carbon (C) atoms.

Answer 1

"The number of oxygen atoms (O) is less than the sum of the sodium (Na), hydrogen (H), and carbon (C) atoms."

This is because in the molecule 3NaHCO3 (sodium bicarbonate), there are three sodium (Na) atoms, three hydrogen (H) atoms, three carbon (C) atoms, but nine oxygen (O) atoms. So, the number of oxygen atoms is indeed more preponderant than the sum of sodium, hydrogen, and carbon atoms.

Answer 2

thank you very much!