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Mathematics 15 Online
jayfafr:

help math nerds pls

jayfafr:

babymay:

the top one x=8 the bottom x=13

UhhhKhakis:

@jhonyy9

jayfafr:

@babymay wrote:
the top one x=8 the bottom x=13
doesnt work like that they both have to be the same

babymay:

hold up my bad

babymay:

x=-17

Extrinix:

Explain it.

babymay:

ask google thats what i did

jayfafr:

i actually dont know didnt really pay atteion i was slumped

babymay:

lmao

jayfafr:

i just know there both suppose to be the same

SmoothCriminal:

To solve the equation \(\frac{x-3}{x-7} = \frac{5}{6}\), you can follow these steps: 1. First, cross-multiply to eliminate the fractions. Multiply both sides of the equation by \(6(x-7)\) to dispense the fractions: \(\frac{x-3}{x-7} \cdot 6(x-7) = \frac{5}{6} \cdot 6(x-7)\). This simplifies to: \(6(x-3) = 5(x-7)\). 2. Now, distribute the numbers on both sides of the equation: \(6x - 18 = 5x - 35\). 3. Next, move all the terms with \(x\) to one side of the equation and the constants to the other side. Subtract \(5x\) from both sides: \(6x - 5x - 18 = -35\). This simplifies to: \(x - 18 = -35\). 4. Conclusively, isolate \(x\) by integrating 18 to both sides of the equation: \(x = -35 + 18\). \(x = -17\). So, the solution to the equation is \(x = -17\).

jayfafr:

@smoothcriminal wrote:
To solve the equation \(\frac{x-3}{x-7} = \frac{5}{6}\), you can follow these steps: 1. First, cross-multiply to eliminate the fractions. Multiply both sides of the equation by \(6(x-7)\) to dispense the fractions: \(\frac{x-3}{x-7} \cdot 6(x-7) = \frac{5}{6} \cdot 6(x-7)\). This simplifies to: \(6(x-3) = 5(x-7)\). 2. Now, distribute the numbers on both sides of the equation: \(6x - 18 = 5x - 35\). 3. Next, move all the terms with \(x\) to one side of the equation and the constants to the other side. Subtract \(5x\) from both sides: \(6x - 5x - 18 = -35\). This simplifies to: \(x - 18 = -35\). 4. Conclusively, isolate \(x\) by integrating 18 to both sides of the equation: \(x = -35 + 18\). \(x = -17\). So, the solution to the equation is \(x = -17\).
W manz

babymay:

thats what google said

SmoothCriminal:

@jayfafr wrote:
@smoothcriminal wrote:
To solve the equation \(\frac{x-3}{x-7} = \frac{5}{6}\), you can follow these steps: 1. First, cross-multiply to eliminate the fractions. Multiply both sides of the equation by \(6(x-7)\) to dispense the fractions: \(\frac{x-3}{x-7} \cdot 6(x-7) = \frac{5}{6} \cdot 6(x-7)\). This simplifies to: \(6(x-3) = 5(x-7)\). 2. Now, distribute the numbers on both sides of the equation: \(6x - 18 = 5x - 35\). 3. Next, move all the terms with \(x\) to one side of the equation and the constants to the other side. Subtract \(5x\) from both sides: \(6x - 5x - 18 = -35\). This simplifies to: \(x - 18 = -35\). 4. Conclusively, isolate \(x\) by integrating 18 to both sides of the equation: \(x = -35 + 18\). \(x = -17\). So, the solution to the equation is \(x = -17\).
W manz
No problem man. These guys will get you killed. 🤦‍♂️ 😂

jayfafr:

@smoothcriminal wrote:
@jayfafr wrote:
@smoothcriminal wrote:
To solve the equation \(\frac{x-3}{x-7} = \frac{5}{6}\), you can follow these steps: 1. First, cross-multiply to eliminate the fractions. Multiply both sides of the equation by \(6(x-7)\) to dispense the fractions: \(\frac{x-3}{x-7} \cdot 6(x-7) = \frac{5}{6} \cdot 6(x-7)\). This simplifies to: \(6(x-3) = 5(x-7)\). 2. Now, distribute the numbers on both sides of the equation: \(6x - 18 = 5x - 35\). 3. Next, move all the terms with \(x\) to one side of the equation and the constants to the other side. Subtract \(5x\) from both sides: \(6x - 5x - 18 = -35\). This simplifies to: \(x - 18 = -35\). 4. Conclusively, isolate \(x\) by integrating 18 to both sides of the equation: \(x = -35 + 18\). \(x = -17\). So, the solution to the equation is \(x = -17\).
W manz
No problem man. These guys will get you killed. 🤦‍♂️ 😂
fr not finna pass nun

babymay:

hey i actually have good grades don't play with it

babymay:

i jus ain't a nerd

jayfafr:

cap

jayfafr:

no you are only a nerd

UhhhKhakis:

"only"

UhhhKhakis:

im weak asl

jayfafr:

your on level 68 wth

UhhhKhakis:

@jayfafr wrote:
your on level 68 wth
I'm gucci fr tho

UhhhKhakis:

ion nerd out like the others

jayfafr:

damn bro you a sweat

jayfafr:

keep up the grind

UhhhKhakis:

nah its just fans and texting

UhhhKhakis:

Ion answer no questions lmao

jayfafr:

shii im bout to do that then

SmoothCriminal:

They said there's a guy who leveled himself to whatever level he wanted to overnight. 👀

jayfafr:

how i do that

UhhhKhakis:

LMAO

SmoothCriminal:

@jayfafr wrote:
how i do that
That's what I wanna know

UhhhKhakis:

You don't want to do that 😂

jayfafr:

yea i do

jayfafr:

i wanna be on leve 69

SmoothCriminal:

@jayfafr wrote:
i wanna be on leve 69
Or 99 👀

Extrinix:

Here was my response before the wifi decided to cut out lmao. (I know it's already been answered dw) "If you're solving for linear proportions, you want to cross multiply. \(\dfrac{x-3}{x-7} = \dfrac{5}{6}\) \(6(x-3) = 5(x-7)\) This when simplified gets you. \(6x-18 = 5x-35\) You then want to get \(x\) by itself, so add 18 to both sides. \(6x = 5x-17\) Now you can subtract 5x from both sides. \(x = -17\) "

jayfafr:

@extrinix wrote:
Here was my response before the wifi decided to cut out lmao. (I know it's already been answered dw) "If you're solving for linear proportions, you want to cross multiply. \(\dfrac{x-3}{x-7} = \dfrac{5}{6}\) \(6(x-3) = 5(x-7)\) This when simplified gets you. \(6x-18 = 5x-35\) You then want to get \(x\) by itself, so add 18 to both sides. \(6x = 5x-17\) Now you can subtract 5x from both sides. \(x = -17\) "
your a lil late

jayfafr:

@extrinix wrote:
Here was my response before the wifi decided to cut out lmao. (I know it's already been answered dw) "If you're solving for linear proportions, you want to cross multiply. \(\dfrac{x-3}{x-7} = \dfrac{5}{6}\) \(6(x-3) = 5(x-7)\) This when simplified gets you. \(6x-18 = 5x-35\) You then want to get \(x\) by itself, so add 18 to both sides. \(6x = 5x-17\) Now you can subtract 5x from both sides. \(x = -17\) "
but thanks anyway

SmoothCriminal:

@jayfafr wrote:
@extrinix wrote:
Here was my response before the wifi decided to cut out lmao. (I know it's already been answered dw) "If you're solving for linear proportions, you want to cross multiply. \(\dfrac{x-3}{x-7} = \dfrac{5}{6}\) \(6(x-3) = 5(x-7)\) This when simplified gets you. \(6x-18 = 5x-35\) You then want to get \(x\) by itself, so add 18 to both sides. \(6x = 5x-17\) Now you can subtract 5x from both sides. \(x = -17\) "
your a lil late
😂😂😂

jayfafr:

yo yall tryna help me with this one to

jayfafr:

i gyat to do 4 more questions

jayfafr:

3*

SmoothCriminal:

@jayfafr wrote:
3*
Sure

jayfafr:

Extrinix:

Do the same thing as previously, cross multiply and solve it from there.

jayfafr:

im broke i dont own paper or penicl

jayfafr:

pencil*

Extrinix:

\(2(3x+9) = 9(x-9)\) I got you started, use the explanations from me and the other responder to answer it.

SmoothCriminal:

\(\frac{x-9}{3x+9} = \frac{2}{9}\) : 1. Cross-multiply to eliminate the fractions. Multiply both sides of the equation by \(9(3x+9)\) to dispense the fractions: \(\frac{x-9}{3x+9} \cdot 9(3x+9) = \frac{2}{9} \cdot 9(3x+9)\). This simplifies to: \(x - 9 = 2(3x+9)\). 2. Now, distribute the 2 on the right side of the equation: \(x - 9 = 6x + 18\). 3. Move all the terms with \(x\) to one side of the equation and the constants to the other side. Subtract \(6x\) from both sides: \(x - 6x - 9 = 18\). This simplifies to: \(-5x - 9 = 18\). 4. Isolate \(x\) by integrating 9 to both sides of the equation: \(-5x = 18 + 9\). \(-5x = 27\). Now, divide both sides by -5 to find \(x\): \(x = \frac{27}{-5}\). \(x = -\frac{27}{5}\). So, the solution to the equation is \(x = -\frac{27}{5}\).

jayfafr:

wasnt right i only have one time to get it right time to clutch

SmoothCriminal:

@jayfafr wrote:
wasnt right i only have one time to get it right time to clutch
You said mine wasn't right?? 😲

jayfafr:

@smoothcriminal wrote:
@jayfafr wrote:
wasnt right i only have one time to get it right time to clutch
You said mine wasn't right?? 😲
yea you sold me

SmoothCriminal:

@jayfafr wrote:
@smoothcriminal wrote:
@jayfafr wrote:
wasnt right i only have one time to get it right time to clutch
You said mine wasn't right?? 😲
yea you sold me
You put \frac{27}{5}\).

SmoothCriminal:

The negative sign I mean

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