doesnt work like that they both have to be the same
babymay:
hold up
my bad
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
babymay:
x=-17
Extrinix:
Explain it.
babymay:
ask google thats what i did
jayfafr:
i actually dont know didnt really pay atteion i was slumped
babymay:
lmao
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
jayfafr:
i just know there both suppose to be the same
SmoothCriminal:
To solve the equation \(\frac{x-3}{x-7} = \frac{5}{6}\), you can follow these steps:
1. First, cross-multiply to eliminate the fractions. Multiply both sides of the equation by \(6(x-7)\) to dispense the fractions:
\(\frac{x-3}{x-7} \cdot 6(x-7) = \frac{5}{6} \cdot 6(x-7)\).
This simplifies to:
\(6(x-3) = 5(x-7)\).
2. Now, distribute the numbers on both sides of the equation:
\(6x - 18 = 5x - 35\).
3. Next, move all the terms with \(x\) to one side of the equation and the constants to the other side. Subtract \(5x\) from both sides:
\(6x - 5x - 18 = -35\).
This simplifies to:
\(x - 18 = -35\).
4. Conclusively, isolate \(x\) by integrating 18 to both sides of the equation:
\(x = -35 + 18\).
\(x = -17\).
So, the solution to the equation is \(x = -17\).
jayfafr:
@smoothcriminal wrote:
To solve the equation \(\frac{x-3}{x-7} = \frac{5}{6}\), you can follow these steps:
1. First, cross-multiply to eliminate the fractions. Multiply both sides of the equation by \(6(x-7)\) to dispense the fractions:
\(\frac{x-3}{x-7} \cdot 6(x-7) = \frac{5}{6} \cdot 6(x-7)\).
This simplifies to:
\(6(x-3) = 5(x-7)\).
2. Now, distribute the numbers on both sides of the equation:
\(6x - 18 = 5x - 35\).
3. Next, move all the terms with \(x\) to one side of the equation and the constants to the other side. Subtract \(5x\) from both sides:
\(6x - 5x - 18 = -35\).
This simplifies to:
\(x - 18 = -35\).
4. Conclusively, isolate \(x\) by integrating 18 to both sides of the equation:
\(x = -35 + 18\).
\(x = -17\).
So, the solution to the equation is \(x = -17\).
W manz
babymay:
thats what google said
SmoothCriminal:
@jayfafr wrote:
@smoothcriminal wrote:
To solve the equation \(\frac{x-3}{x-7} = \frac{5}{6}\), you can follow these steps:
1. First, cross-multiply to eliminate the fractions. Multiply both sides of the equation by \(6(x-7)\) to dispense the fractions:
\(\frac{x-3}{x-7} \cdot 6(x-7) = \frac{5}{6} \cdot 6(x-7)\).
This simplifies to:
\(6(x-3) = 5(x-7)\).
2. Now, distribute the numbers on both sides of the equation:
\(6x - 18 = 5x - 35\).
3. Next, move all the terms with \(x\) to one side of the equation and the constants to the other side. Subtract \(5x\) from both sides:
\(6x - 5x - 18 = -35\).
This simplifies to:
\(x - 18 = -35\).
4. Conclusively, isolate \(x\) by integrating 18 to both sides of the equation:
\(x = -35 + 18\).
\(x = -17\).
So, the solution to the equation is \(x = -17\).
W manz
No problem man. These guys will get you killed. 🤦♂️ 😂
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
jayfafr:
@smoothcriminal wrote:
@jayfafr wrote:
@smoothcriminal wrote:
To solve the equation \(\frac{x-3}{x-7} = \frac{5}{6}\), you can follow these steps:
1. First, cross-multiply to eliminate the fractions. Multiply both sides of the equation by \(6(x-7)\) to dispense the fractions:
\(\frac{x-3}{x-7} \cdot 6(x-7) = \frac{5}{6} \cdot 6(x-7)\).
This simplifies to:
\(6(x-3) = 5(x-7)\).
2. Now, distribute the numbers on both sides of the equation:
\(6x - 18 = 5x - 35\).
3. Next, move all the terms with \(x\) to one side of the equation and the constants to the other side. Subtract \(5x\) from both sides:
\(6x - 5x - 18 = -35\).
This simplifies to:
\(x - 18 = -35\).
4. Conclusively, isolate \(x\) by integrating 18 to both sides of the equation:
\(x = -35 + 18\).
\(x = -17\).
So, the solution to the equation is \(x = -17\).
W manz
No problem man. These guys will get you killed. 🤦♂️ 😂
fr not finna pass nun
babymay:
hey i actually have good grades don't play with it
babymay:
i jus ain't a nerd
jayfafr:
cap
jayfafr:
no you are only a nerd
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
UhhhKhakis:
"only"
UhhhKhakis:
im weak asl
jayfafr:
your on level 68 wth
UhhhKhakis:
@jayfafr wrote:
your on level 68 wth
I'm gucci fr tho
UhhhKhakis:
ion nerd out like the others
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
jayfafr:
damn bro you a sweat
jayfafr:
keep up the grind
UhhhKhakis:
nah its just fans and texting
UhhhKhakis:
Ion answer no questions lmao
jayfafr:
shii im bout to do that then
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
SmoothCriminal:
They said there's a guy who leveled himself to whatever level he wanted to overnight. 👀
jayfafr:
how i do that
UhhhKhakis:
LMAO
SmoothCriminal:
@jayfafr wrote:
how i do that
That's what I wanna know
UhhhKhakis:
You don't want to do that 😂
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
jayfafr:
yea i do
jayfafr:
i wanna be on leve 69
SmoothCriminal:
@jayfafr wrote:
i wanna be on leve 69
Or 99 👀
Extrinix:
Here was my response before the wifi decided to cut out lmao. (I know it's already been answered dw)
"If you're solving for linear proportions, you want to cross multiply.
\(\dfrac{x-3}{x-7} = \dfrac{5}{6}\)
\(6(x-3) = 5(x-7)\)
This when simplified gets you.
\(6x-18 = 5x-35\)
You then want to get \(x\) by itself, so add 18 to both sides.
\(6x = 5x-17\)
Now you can subtract 5x from both sides.
\(x = -17\) "
jayfafr:
@extrinix wrote:
Here was my response before the wifi decided to cut out lmao. (I know it's already been answered dw)
"If you're solving for linear proportions, you want to cross multiply.
\(\dfrac{x-3}{x-7} = \dfrac{5}{6}\)
\(6(x-3) = 5(x-7)\)
This when simplified gets you.
\(6x-18 = 5x-35\)
You then want to get \(x\) by itself, so add 18 to both sides.
\(6x = 5x-17\)
Now you can subtract 5x from both sides.
\(x = -17\) "
your a lil late
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
jayfafr:
@extrinix wrote:
Here was my response before the wifi decided to cut out lmao. (I know it's already been answered dw)
"If you're solving for linear proportions, you want to cross multiply.
\(\dfrac{x-3}{x-7} = \dfrac{5}{6}\)
\(6(x-3) = 5(x-7)\)
This when simplified gets you.
\(6x-18 = 5x-35\)
You then want to get \(x\) by itself, so add 18 to both sides.
\(6x = 5x-17\)
Now you can subtract 5x from both sides.
\(x = -17\) "
but thanks anyway
SmoothCriminal:
@jayfafr wrote:
@extrinix wrote:
Here was my response before the wifi decided to cut out lmao. (I know it's already been answered dw)
"If you're solving for linear proportions, you want to cross multiply.
\(\dfrac{x-3}{x-7} = \dfrac{5}{6}\)
\(6(x-3) = 5(x-7)\)
This when simplified gets you.
\(6x-18 = 5x-35\)
You then want to get \(x\) by itself, so add 18 to both sides.
\(6x = 5x-17\)
Now you can subtract 5x from both sides.
\(x = -17\) "
your a lil late
😂😂😂
jayfafr:
yo yall tryna help me with this one to
jayfafr:
i gyat to do 4 more questions
jayfafr:
3*
Still Need Help?
Join the QuestionCove community and study together with friends!
Do the same thing as previously, cross multiply and solve it from there.
jayfafr:
im broke i dont own paper or penicl
jayfafr:
pencil*
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
Extrinix:
\(2(3x+9) = 9(x-9)\)
I got you started, use the explanations from me and the other responder to answer it.
SmoothCriminal:
\(\frac{x-9}{3x+9} = \frac{2}{9}\) :
1. Cross-multiply to eliminate the fractions. Multiply both sides of the equation by \(9(3x+9)\) to dispense the fractions:
\(\frac{x-9}{3x+9} \cdot 9(3x+9) = \frac{2}{9} \cdot 9(3x+9)\).
This simplifies to:
\(x - 9 = 2(3x+9)\).
2. Now, distribute the 2 on the right side of the equation:
\(x - 9 = 6x + 18\).
3. Move all the terms with \(x\) to one side of the equation and the constants to the other side. Subtract \(6x\) from both sides:
\(x - 6x - 9 = 18\).
This simplifies to:
\(-5x - 9 = 18\).
4. Isolate \(x\) by integrating 9 to both sides of the equation:
\(-5x = 18 + 9\).
\(-5x = 27\).
Now, divide both sides by -5 to find \(x\):
\(x = \frac{27}{-5}\).
\(x = -\frac{27}{5}\).
So, the solution to the equation is \(x = -\frac{27}{5}\).
jayfafr:
wasnt right i only have one time to get it right time to clutch
SmoothCriminal:
@jayfafr wrote:
wasnt right i only have one time to get it right time to clutch
You said mine wasn't right?? 😲
jayfafr:
@smoothcriminal wrote:
@jayfafr wrote:
wasnt right i only have one time to get it right time to clutch
You said mine wasn't right?? 😲
yea you sold me
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
SmoothCriminal:
@jayfafr wrote:
@smoothcriminal wrote:
@jayfafr wrote:
wasnt right i only have one time to get it right time to clutch