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umm:
Does your question look like this?
\[\frac{ x-9 }{ 3x+9 }=\frac{ 5 }{ 6 }\]
MiaTatem23:
@umm wrote:
Does your question look like this?
\[\frac{ x-9 }{ 3x+9 }=\frac{ 5 }{ 6 }\]
Yes
umm:
Alright, what are we trying to figure out? If the value is true or not?
MiaTatem23:
@umm wrote:
Alright, what are we trying to figure out? If the value is true or not?
I think so
MiaTatem23:
I'm rusty as hell
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umm:
Do you happen to have a screenshot of your math problem? Just want to double check. You can take a screen capture and it'd copy it, so ctrl + v would paste it here.
umm:
Yes. Does it have answer choices, or explain further than that?
I know how to help, I'm just trying to figure out if that's all we need to do is prove that's our answer or not.
Yes. Does it have answer choices, or explain further than that?
I know how to help, I'm just trying to figure out if that's all we need to do is prove that's our answer or not.
I'm supposed to remember from lesson 48 but that was last year so idk
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Extrinix:
@umm it's solving for linear proportions.
Extrinix:
I had a very similar question about an hour ago.
umm:
@extrinix wrote:
@umm it's solving for linear proportions.
Thank you, I figured.
umm:
Alright, let's get started.
Given: \[\frac{ x-9 }{ 3x+9 }=\frac{ 5 }{ 6 }\]
Do you know how to cross multiply?
Example:
\[\frac{ a }{ b }=\frac{ c }{ d }\]
Then:\[a \times d = b \times c \]
MiaTatem23:
Oh damn
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MiaTatem23:
at least tell me what to do first
umm:
I have, with the cross multiply.
MiaTatem23:
@umm wrote:
I have, with the cross multiply.
ik ik what do i cross multiply
umm:
The given equation:
\[\frac{ x-9 }{ 3x+9 }=\frac{ 5 }{ 6 }\]
MiaTatem23:
bro I don't know what to do first tho ðŸ˜
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MiaTatem23:
I know cross multiply but cross multiply whattt
umm:
@umm wrote:
Alright, let's get started.
Given: \[\frac{ x-9 }{ 3x+9 }=\frac{ 5 }{ 6 }\]
Do you know how to cross multiply?
Example:
\[\frac{ a }{ b }=\frac{ c }{ d }\]
Then:\[a \times d = b \times c \]
MiaTatem23:
Ok I forgot how to cross multiply..
MiaTatem23:
do what now?
umm:
Think of x-9 as a from the given example and continue from there.
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MiaTatem23:
So what by 9 will equal 5?
MiaTatem23:
@umm wrote:
Think of x-9 as a from the given example and continue from there.
*dies inside* 💀
umm:
No, here, I'll show you. Just so you know, I won't be doing this all for you.
\[(x-9) \times 6 - (3x+9) \times 5\]
MiaTatem23:
@umm wrote:
No, here, I'll show you. Just so you know, I won't be doing this all for you.
\[(x-9) \times 6 - (3x+9) \times 5\]
I don't understand tho..
umm:
What are you not understanding?
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MiaTatem23:
@umm wrote:
No, here, I'll show you. Just so you know, I won't be doing this all for you.
\[(x-9) \times 6 - (3x+9) \times 5\]
I guess idk what I'm supposed to do 👆
umm:
Did you not read how I showed you in the example?
MiaTatem23:
@umm wrote:
Did you not read how I showed you in the example?
I did but don't get it
MiaTatem23:
Still..
Extrinix:
I'll give you an example on behalf of umm just so you can make sense of it.
Original problem:
\(\dfrac{1x}{2} = \dfrac{3}{4}\)
Cross multiply:
\(3(2) = 1x(4)\)
Simplify:
\(6 = 4x\)
Divide:
\(\dfrac{6}{4} = \dfrac{4x}{4}\)
Solve:
\(1\dfrac{1}{2} = x\)
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MiaTatem23:
@extrinix wrote:
I'll give you an example on behalf of umm just so you can make sense of it.
Original problem:
\(\dfrac{1x}{2} = \dfrac{3}{4}\)
Cross multiply:
\(3(2) = 1x(4)\)
Simplify:
\(6 = 4x\)
Divide:
\(\dfrac{6}{4} = \dfrac{4x}{4}\)
Solve:
\(1\dfrac{1}{2} = x\)
Oh my god that makes more sense!
Extrinix:
There's a simple problem on how to do cross multiplication, it's not that hard, you just have to remember this:
\(\dfrac{\color{tomato}{a}}{\color{cyan}{b}} = \dfrac{\color{violet}{c}}{\color{lime}{d}}\)
is the same as
\(\color{lime}{d}(\color{tomato}{a}) = \color{cyan}{b}(\color{violet}{c})\)
MiaTatem23:
@extrinix wrote:
There's a simple problem on how to do cross multiplication, it's not that hard, you just have to remember this:
\(\dfrac{\color{tomato}{a}}{\color{cyan}{b}} = \dfrac{\color{violet}{c}}{\color{lime}{d}}\)
is the same as
\(\color{lime}{d}(\color{tomato}{a}) = \color{cyan}{b}(\color{violet}{c})\)
So does x = -11? That's what I got just now
umm:
@extrinix wrote:
There's a simple problem on how to do cross multiplication, it's not that hard, you just have to remember this:
\(\dfrac{\color{tomato}{a}}{\color{cyan}{b}} = \dfrac{\color{violet}{c}}{\color{lime}{d}}\)
is the same as
\(\color{lime}{d}(\color{tomato}{a}) = \color{cyan}{b}(\color{violet}{c})\)
Thank you, I was trying to actually draw this out and I'm on mobile, lol.