i literally suck at this and this is the only question i need help with, so any help would be nice :)
chuckthedonut:
okay, nevermind i'll try and figure it out myself.
Luigi0210:
Did you figure it out? Lemme answer it for you anyways, so we start off with this:
\[\large 2\frac{1}{2}x -\frac{3}{4}(2x+5)=\frac{3}{8} \]
First, you have to distribute the 3/4 out into the parentheses:
\[\large 2\frac{1}{2}x -(\frac{3}{4}(2x)+\frac{3}{4}(5))=\frac{3}{8} \]
Don't forget that it's *negative* 3/4 so:
\[\large 2\frac{1}{2}x -\frac{3}{4}(2x)-\frac{3}{4}(5)=\frac{3}{8} \]
Now just multiply it out:
\[\large 2\frac{1}{2}x -\frac{6}{4}x-\frac{15}{4}=\frac{3}{8} \]
The 6/4 can be simplified, and the 2(1/2) can be changed:
\[\large \frac{5}{2}x -\frac{3}{2}x-\frac{15}{4}=\frac{3}{8} \]
Now, just move -15/4 to the other side of the equation, and combine the x terms:
\[\large \frac{2}{2}x=\frac{3}{8}+\frac{15}{4} \]
multiply the 15/4 by 2 and you can add the fractions; and 2/2 is just one, so you get:
\[\large x=\frac{33}{8} \]
Since 8 can go into 33, four times, you can pull out a 4:
\[\large x=4\frac{1}{8} \]
chuckthedonut:
@luigi0210 wrote:
Did you figure it out? Lemme answer it for you anyways, so we start off with this:
\[\large 2\frac{1}{2}x -\frac{3}{4}(2x+5)=\frac{3}{8} \]
First, you have to distribute the 3/4 out into the parentheses:
\[\large 2\frac{1}{2}x -(\frac{3}{4}(2x)+\frac{3}{4}(5))=\frac{3}{8} \]
Don't forget that it's *negative* 3/4 so:
\[\large 2\frac{1}{2}x -\frac{3}{4}(2x)-\frac{3}{4}(5)=\frac{3}{8} \]
Now just multiply it out:
\[\large 2\frac{1}{2}x -\frac{6}{4}x-\frac{15}{4}=\frac{3}{8} \]
The 6/4 can be simplified, and the 2(1/2) can be changed:
\[\large \frac{5}{2}x -\frac{3}{2}x-\frac{15}{4}=\frac{3}{8} \]
Now, just move -15/4 to the other side of the equation, and combine the x terms:
\[\large \frac{2}{2}x=\frac{3}{8}+\frac{15}{4} \]
multiply the 15/4 by 2 and you can add the fractions; and 2/2 is just one, so you get:
\[\large x=\frac{33}{8} \]
Since 8 can go into 33, four times, you can pull out a 4:
\[\large x=4\frac{1}{8} \]
this was the correct answer, i got 5/5 on it ! thank you ! :D