Question

Can anyone help me with this?
(Stoichiometry)

Answer 1

why

Answer 2

First thing you have to do, is balance the equation, which lucky for you is already balanced.

Next, convert the 6 g of Mg given into moles:
\[\large 6g~Mg*\frac{1 mol}{24 g~Mg} =0.25~ mol\]
The grams of Mg will cancel. Now, convert the moles of Mg to moles of MgSO4.
In this case, it is a 1-to-1 ratio. The molecular weight of MgSO4 is 120 mg (from the weights given in the problem).

\[\Large 0.25~mol*\frac{120 g~MgSO_4}{1 ~mol} = 30~g~MgSO_4\]

Answer 3

thank you very much!