Question

Maximum possible zeroes for the polynomial
f(x)=-2x^8+2x^5-x^4+5x^2-9

Answer 1

hmm i dont think i know this one tbh

Answer 2

In order to isolate the variable in this linear equation, we need to get rid of the coefficient that multiplies it.

This can be accomplished if both sides are divided by x .

Answer 3

-2x^7+2x^4-x^3+5x-9?

Answer 4

So 3 zeroes, since the degree is a zero?

Answer 5

ax^n-1 for 2x^4, which is 2x^4-1=2x^3 = 3 zeroes

Answer 6

@swirxy Thanks for the help

Answer 7

Yw

Answer 8

as it is of degree 8.
possible number of zeros=8
f(x)=-2x^8+2x^5-x^4+5x^2-9
signs of f(x)=- + - + -9
no. of sign changes =4
so there are at the most 4 positive zeros.
f(-x)=-2x^8-2x^5-x^4+5x^2-9
signs of f(-x)=- - - + -
no. of sign changes in f(-x)=2
Hence there are two negative zeros.