help

Question

help

LettuceXLard · Answer

no

ihatelifeFS420 · Answer

attachment

5StarFab · Answer

Did you even learn how to do it after oliver told you numerous times?

ihatelifeFS420 · Answer

@5starfab wrote:

Did you even learn how to do it after oliver told you numerous times?

omg st.fu and get off my fcking post

5StarFab · Answer

Answer my question first.

ihatelifeFS420 · Answer

@5starfab wrote:

Answer my question first.

yes I did but I have a hard time retaining stuff

5StarFab · Answer

That's why you ask your teacher and don't rely on the net for answers.

5StarFab · Answer

The teacher made the google forms.So they have the answers.

ihatelifeFS420 · Answer

@5starfab wrote:

That's why you ask your teacher and don't rely on the net for answers.

I don't even retain what my teacher says half the time and it's not google forms it's called big ideas math thank you very much

OLIVER69 · Answer

The vertex form of a quadratic function is y = a(x – h)^2 + k, where a, h, and k are constants. of the parabola is at (h, k).

(h, k) would be the vertex of the parabola, and the vertex is (8,3)

So plug (4,-1) into h and k in the equation above.

It should look like y = a(x-8)^2 + 3

And A is the direction the parabola moved. which is 4.

So your equation should be y=4(x-8)^2 + 3

I hope this is correct and that I could help in some way

ihatelifeFS420 · Answer

@oliver69 wrote:

The vertex form of a quadratic function is y = a(x – h)^2 + k, where a, h, and k are constants. of the parabola is at (h, k). (h, k) would be the vertex of the parabola, and the vertex is (8,3) So plug (4,-1) into h and k in the equation above. It should look like y = a(x-8)^2 + 3 And A is the direction the parabola moved. which is 4. So your equation should be y=4(x-8)^2 + 3 I hope this is correct and that I could help in some way

thank you

ihatelifeFS420 · Answer

it isnt right

5StarFab · Answer

@ihatelifefs420 wrote:

it isnt right

This is why you don't ask for help on the net.

1 attachment