Question

ummmmmmm hep me please

Answer 1

idk what to do

Answer 2

\[3 (z + 8) = 3 \times (z + 8)\]

If we want z + 8 alone, we have to remove the 3. The number 3 is doing the equivalent of multiplying z + 8 by 3. What is the opposite of multiplication that we could do to 'remove' the 3?

Answer 3

division correct?

Answer 4

The next step is identifying that this would be division.

And in order to 'remove' the number, you must know that any number divided by itself is 1

So \[3 \div 3 = 1\]

So we do

\[\frac{ 3 (z + 8) }{ 3 } = \frac{ 15 }{ 3 }\]

In order to keep the equation true, what we do to ONE side, we must do to the other.

Answer 5

\[z + 8 = 5\]

This is what you should get.

From there you need to further isolate z to see what that value of it is.

Since 8 is being added to z, we can do the opposite operation to it to remove it.

So subtract 8 from both sides

\[z + 8 - 8 = 5 - 8\]
\[z = 5 - 8 = -3\]

Answer 6

You can check your work by inputting the number -3 back into the equation\[3(-3 + 8) = 15\]
\[3(5) = 15 \rightarrow 15 = 15\]

Answer 7

thnk u

Answer 8

You're welcome