Question

help mee

Answer 1

Segment GH is shown on the graph.

Answer 2

What are the coordinates of the point that divides the segment into a 3:2 ratio?

(–7.5, 0.5)
(0.5, –7.5)
(–1.2, –2.2)
(–2.2, –1.2)

Answer 3

idk how to ss im sorry

Answer 4

in the menu at the bottom where the time is shown you should be able to see "screen capture" .

Answer 5

welp imma have to resort to my only choice
guessing

Answer 6

By the information given .

Answer 7

It seems like it could be D .

Answer 8

If the endpoints of AB are A(–2, 3) and B(1, 8), which shows the correct way to determine the coordinates of point C, the midpoint of AB?

Answer 9

is it a multi choice ? .

Answer 10

yeah but i googled it

Answer 11

thanks for ya'lls help or at least for trying to help me lmaooo

Answer 12

your efforts are seen love youu sm thnx

Answer 13

Sorry, spotty Wi-Fi.


Without a visual representation, I’ll try and explain it as simple as I can.

In simpler terms, if you have two points A and B, and you want to find a point C that's closer to A in a 3:2 ratio, you can find the x-coordinate of C by going three-fifths (3/5) of the way from B to A and the y-coordinate by going three-fifths (3/5) of the way from B to A.

Answer 14

scholar

Answer 15

In order to be able to find the coordinates of the midpoint C of segment AB, you use the midpoint formula. If needed an explanation for midpoint formula, let me know and I can break it down for you.

For points A(-2, 3) and B(1, 8), the coordinates of the midpoint C are calculated as follows:

\[ x = \frac{-2 + 1}{2} \]
\[ y = \frac{3 + 8}{2} \]

The correct way to determine the coordinates of point C, the midpoint of AB, is:

\[ C \left(\frac{-1}{2}, \frac{11}{2}\right) \]

And a section way to find the midpoint is by averaging the x-coordinates and y-coordinates of points A and B:

\[ x = \frac{-2 + 1}{2} \]

\[ y = \frac{3 + 8}{2} \]

This gives you the coordinates of C as \((-0.5, 5.5)\). So, both methods yield the same result, confirming that the midpoint of AB is \((-0.5, 5.5)\).