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Help Asap Please

OLIVER69 · Answer

Each day a student goes to Starbucks with a probability of .6, goes to McDonalds with a probability of .45, and goes to neither with a probability of .15.

Find the probability the students goes to either Starbucks or McDonalds, but not both.

spyeye · Answer

boody cheecks my mom smacks

spyeye · Answer

mb lol i had to

toga · Answer

To find the probability of a student going to either Starbucks or McDonald's, but not both, we need to calculate the probability of them going to each place exclusively. The probability of going to Starbucks but not McDonald's is 0.57, and the probability of going to McDonald's but not Starbucks is 0.27. Adding these probabilities gives us the probability of the student going to either Starbucks or McDonald's, but not both, which is 0.84.

umm · Answer

@toga wrote:

To find the probability of a student going to either Starbucks or McDonald's, but not both, we need to calculate the probability of them going to each place exclusively. The probability of going to Starbucks but not McDonald's is 0.57, and the probability of going to McDonald's but not Starbucks is 0.27. Adding these probabilities gives us the probability of the student going to either Starbucks or McDonald's, but not both, which is 0.84.

This seems to be incorrect. Complementary events in probability are like the flip side of a coin. If you're looking at the chance of something happening, the complementary event is about that thing not happening. Imagine rolling a dice, if you're interested in getting a 4, the complementary event is not getting a 4, which could be any other number from 1 to 6. We often express this as fractions; if the chance of drawing a red ball is $\frac{1}{3}$, then the chance of not getting a red ball is $\frac{2}{3}$. What's interesting is that when you add the chance of an event and its complement, it always equals 1, helping us see the whole probability picture. To find the probability the student goes to either Starbucks or McDonald's, but not both, you can sum the individual probabilities of going to each place and then subtract twice the probability of going to both places (intersection). $$ P(\text{Starbucks or McDonald's, but not both}) = P(\text{Starbucks}) + P(\text{McDonald's}) - 2 \times P(\text{Starbucks and McDonald's}) $$ $$ = 0.6 + 0.45 - 2 \times 0.6 \times 0.45 $$ $$ = 0.6 + 0.45 - 2 \times 0.27 $$ $$ = 0.6 + 0.45 - 0.54 $$ $$ = 0.51 $$ So, the probability the student goes to either Starbucks or McDonald's, but not both, is $0.51$.

toga · Answer

@umm wrote:

@toga wrote:

To find the probability of a student going to either Starbucks or McDonald's, but not both, we need to calculate the probability of them going to each place exclusively. The probability of going to Starbucks but not McDonald's is 0.57, and the probability of going to McDonald's but not Starbucks is 0.27. Adding these probabilities gives us the probability of the student going to either Starbucks or McDonald's, but not both, which is 0.84.

This seems to be incorrect. Complementary events in probability are like the flip side of a coin. If you're looking at the chance of something happening, the complementary event is about that thing not happening. Imagine rolling a dice, if you're interested in getting a 4, the complementary event is not getting a 4, which could be any other number from 1 to 6. We often express this as fractions; if the chance of drawing a red ball is $\frac{1}{3}$, then the chance of not getting a red ball is $\frac{2}{3}$. What's interesting is that when you add the chance of an event and its complement, it always equals 1, helping us see the whole probability picture. To find the probability the student goes to either Starbucks or McDonald's, but not both, you can sum the individual probabilities of going to each place and then subtract twice the probability of going to both places (intersection). $$ P(\text{Starbucks or McDonald's, but not both}) = P(\text{Starbucks}) + P(\text{McDonald's}) - 2 \times P(\text{Starbucks and McDonald's}) $$ $$ = 0.6 + 0.45 - 2 \times 0.6 \times 0.45 $$ $$ = 0.6 + 0.45 - 2 \times 0.27 $$ $$ = 0.6 + 0.45 - 0.54 $$ $$ = 0.51 $$ So, the probability the student goes to either Starbucks or McDonald's, but not both, is $0.51$.

oh

liliaDdowcipny · Answer

i didn't understand half of that

Yanaisswaggy · Answer

@liliaddowcipny wrote:

i didn't understand half of that

real ash

XxkilleratcodxX · Answer

did u already get the answer?

spyeye · Answer

@xxkilleratcodxx wrote:

did u already get the answer?

nah