A hockey player has a 63% chance of making a penalty shot. If the player's probability of making two shots is 0.497, are the penalty shots independent events? Justify the answer mathematically. Yes, because (0.63)(0.63) = 0.497 No, because (0.63)(0.63) ≠ 0.497 Yes, because 63% + 63% = 49.7% No, because 63% + 63% ≠ 49.7%
Second one
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Why is it the second one?
shes right actually
No, because ( 0.63 ) ( 0.63 ) ≠ 0.497 (0.63)(0.63) =0.497. To determine if two events are independent, we need to check if the probability of both events occurring is equal to the product of their individual probabilities. In this case, the probability of making two shots is not equal to the product of the individual probabilities of making each shot. Therefore, the penalty shots are not independent events.
nvm
oop
yea thats right
@gingy57016 how yk that?
Well, thank you!
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